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Aptitude - Decimal Fraction - Discussion

@ : Home > Aptitude > Decimal Fraction > General Questions - Discussion

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"To err is human; to forgive, divine."
- Alexander Pope
3. 

The value of (0.96)3 - (0.1)3 is:
(0.96)2 + 0.096 + (0.1)2

[A]. 0.86[B]. 0.95
[C]. 0.97[D]. 1.06

Answer: Option A

Explanation:

Given expression
= (0.96)3 - (0.1)3
(0.96)2 + (0.96 x 0.1) + (0.1)2
= a3 - b3
a2 + ab + b2
= (a - b)
= (0.96 - 0.1)
= 0.86


Vignesh said: (Sat, Feb 12, 2011 01:09:12 AM)    
 
Please tell how (a-b) is possible

Gokil said: (Sat, Feb 26, 2011 12:39:00 AM)    
 
How (a-b) possible? please tell.

Shivakarthik said: (Fri, Mar 25, 2011 12:07:45 PM)    
 
The formula for a cube - b cube is (a-b)(a2+ab+b2) this 2 s are squares so we cancel the denominator we get (a-b).

Hope you understand.

Akshu said: (Wed, Jul 27, 2011 02:53:25 PM)    
 
Can tell me clearly please I didn't get.

Jasmine said: (Tue, Sep 20, 2011 06:09:51 PM)    
 
Hi friends,

(0.96)3-(0.1)3/(0.96)2+0.096+(0.1)2

a3-b3/a2+ab+b2 = (a-b)(a2+ab+b2)/(a2+ab+b2) = (a-b)
so a=0.96 and b=0.1

(a-b)=0.96-0.10= 0.86

Kannan said: (Fri, Feb 3, 2012 02:46:05 PM)    
 
How a-b possible ?

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