Aptitude - Decimal Fraction - Discussion
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Read more:"To err is human; to forgive, divine."
- Alexander Pope
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| 3. |
| The value of |
(0.96)3 - (0.1)3 |
is: |
| (0.96)2 + 0.096 + (0.1)2 |
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| [A]. |
0.86 | [B]. |
0.95 | | [C]. |
0.97 | [D]. |
1.06 |
Answer: Option A
Explanation:
| Given expression |
| = |
(0.96)3 - (0.1)3 |
| (0.96)2 + (0.96 x 0.1) + (0.1)2 |
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| = |
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a3 - b3 |
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| a2 + ab + b2 |
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| = (a - b) |
| = (0.96 - 0.1) |
| = 0.86 |
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Vignesh said:
(Sat, Feb 12, 2011 01:09:12 AM)
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| Please tell how (a-b) is possible |
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Gokil said:
(Sat, Feb 26, 2011 12:39:00 AM)
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| How (a-b) possible? please tell. |
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Shivakarthik said:
(Fri, Mar 25, 2011 12:07:45 PM)
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The formula for a cube - b cube is (a-b)(a2+ab+b2) this 2 s are squares so we cancel the denominator we get (a-b).
Hope you understand. |
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Akshu said:
(Wed, Jul 27, 2011 02:53:25 PM)
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| Can tell me clearly please I didn't get. |
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Jasmine said:
(Tue, Sep 20, 2011 06:09:51 PM)
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Hi friends,
(0.96)3-(0.1)3/(0.96)2+0.096+(0.1)2
a3-b3/a2+ab+b2 = (a-b)(a2+ab+b2)/(a2+ab+b2) = (a-b)
so a=0.96 and b=0.1
(a-b)=0.96-0.10= 0.86 |
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Kannan said:
(Fri, Feb 3, 2012 02:46:05 PM)
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| How a-b possible ? |
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