Aptitude - Decimal Fraction - Discussion
Discussion Forum : Decimal Fraction - General Questions (Q.No. 3)
3.
| The value of | (0.96)3 - (0.1)3 | is: |
| (0.96)2 + 0.096 + (0.1)2 |
Answer: Option
Explanation:
| Given expression |
|
|||||
|
||||||
|
Discussion:
22 comments Page 1 of 3.
Vignesh said:
1 decade ago
Please tell how (a-b) is possible
Gokil said:
1 decade ago
How (a-b) possible? please tell.
Shivakarthik said:
1 decade ago
The formula for a cube - b cube is (a-b)(a2+ab+b2) this 2 s are squares so we cancel the denominator we get (a-b).
Hope you understand.
Hope you understand.
Akshu said:
1 decade ago
Can tell me clearly please I didn't get.
Jasmine said:
1 decade ago
Hi friends,
(0.96)3-(0.1)3/(0.96)2+0.096+(0.1)2
a3-b3/a2+ab+b2 = (a-b)(a2+ab+b2)/(a2+ab+b2) = (a-b)
so a=0.96 and b=0.1
(a-b)=0.96-0.10= 0.86
(0.96)3-(0.1)3/(0.96)2+0.096+(0.1)2
a3-b3/a2+ab+b2 = (a-b)(a2+ab+b2)/(a2+ab+b2) = (a-b)
so a=0.96 and b=0.1
(a-b)=0.96-0.10= 0.86
Kannan said:
1 decade ago
How a-b possible ?
Nathi said:
1 decade ago
How is it possible?
Nathi said:
1 decade ago
Hi Friends,
Formula
(a^3-b^3) = (a-b)(a^2+ab+b^2)/a^2+ab+b^2
So cancel thes and we get (a-b).
Formula
(a^3-b^3) = (a-b)(a^2+ab+b^2)/a^2+ab+b^2
So cancel thes and we get (a-b).
Bhumi said:
1 decade ago
How is it possible a-b?
Rajiv kumar said:
1 decade ago
We know that (a-b) ^3= (a-b) (a^2+ab+b^2) now in denominator (a^2+ab+b^2) is already given so we cancel these term we get (a-b).
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers