Aptitude - Decimal Fraction - Discussion
Discussion Forum : Decimal Fraction - General Questions (Q.No. 3)
3.
| The value of | (0.96)3 - (0.1)3 | is: |
| (0.96)2 + 0.096 + (0.1)2 |
Answer: Option
Explanation:
| Given expression |
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Discussion:
22 comments Page 2 of 3.
M.azam said:
1 decade ago
@Vineash.
The formula of a^3-b^3 = (a-b)(a^2+ab+b^2).
Hence a^3-b^3/a^2+ab+b^2 = a-b.
The formula of a^3-b^3 = (a-b)(a^2+ab+b^2).
Hence a^3-b^3/a^2+ab+b^2 = a-b.
Harish said:
1 decade ago
What is formula for:
a^3-b^3 = (a-b)(a^2+b^2+ab).
You got it now we have from question.
a-b = (a^3-b^3)/(a^2+ab+b^2).
LHS = RHS.
So we LHS.
a-b = 0.96-0.1
= 0.86.
a^3-b^3 = (a-b)(a^2+b^2+ab).
You got it now we have from question.
a-b = (a^3-b^3)/(a^2+ab+b^2).
LHS = RHS.
So we LHS.
a-b = 0.96-0.1
= 0.86.
Rajiv kumar said:
1 decade ago
We know that (a-b) ^3= (a-b) (a^2+ab+b^2) now in denominator (a^2+ab+b^2) is already given so we cancel these term we get (a-b).
Bhumi said:
1 decade ago
How is it possible a-b?
Nathi said:
1 decade ago
Hi Friends,
Formula
(a^3-b^3) = (a-b)(a^2+ab+b^2)/a^2+ab+b^2
So cancel thes and we get (a-b).
Formula
(a^3-b^3) = (a-b)(a^2+ab+b^2)/a^2+ab+b^2
So cancel thes and we get (a-b).
Nathi said:
1 decade ago
How is it possible?
Kannan said:
1 decade ago
How a-b possible ?
Jasmine said:
1 decade ago
Hi friends,
(0.96)3-(0.1)3/(0.96)2+0.096+(0.1)2
a3-b3/a2+ab+b2 = (a-b)(a2+ab+b2)/(a2+ab+b2) = (a-b)
so a=0.96 and b=0.1
(a-b)=0.96-0.10= 0.86
(0.96)3-(0.1)3/(0.96)2+0.096+(0.1)2
a3-b3/a2+ab+b2 = (a-b)(a2+ab+b2)/(a2+ab+b2) = (a-b)
so a=0.96 and b=0.1
(a-b)=0.96-0.10= 0.86
Akshu said:
1 decade ago
Can tell me clearly please I didn't get.
Shivakarthik said:
1 decade ago
The formula for a cube - b cube is (a-b)(a2+ab+b2) this 2 s are squares so we cancel the denominator we get (a-b).
Hope you understand.
Hope you understand.
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