Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 6)
6.
What will be the compound interest on a sum of Rs. 25,000 after 3 years at the rate of 12 p.c.p.a.?
Answer: Option
Explanation:
| Amount |
|
||||||||||||
|
|||||||||||||
| = Rs. 35123.20 |
C.I. = Rs. (35123.20 - 25000) = Rs. 10123.20
Discussion:
38 comments Page 1 of 4.
Musadiq Hussain said:
4 years ago
1+12/100 = 112/100 = 28/25.
(28/25)^3 = 1.40,
25000 * 1.40.
(28/25)^3 = 1.40,
25000 * 1.40.
(2)
Dolly said:
4 years ago
Shortcut to find out a compound interest by ratio method.
For 3yrs, the ratio is 331 ie find 12% of 25000,
(12*25000)/100 = 3000,
Then find 12% of 3000.
(12*3000)/100 = 360,
Then find 12% of 360.
(12*360)/100= 43.2.
Now multiply by the ratio and then add.
3000*3 + 360*3 + 43.2*1 = 9000 + 1080 + 43.2 = 10123.3.
For 3yrs, the ratio is 331 ie find 12% of 25000,
(12*25000)/100 = 3000,
Then find 12% of 3000.
(12*3000)/100 = 360,
Then find 12% of 360.
(12*360)/100= 43.2.
Now multiply by the ratio and then add.
3000*3 + 360*3 + 43.2*1 = 9000 + 1080 + 43.2 = 10123.3.
(9)
KJ B Vinothan said:
6 years ago
Rate interest 12 for 3 year.
1st 2 year =a+b+(a*b/100)=12+12+(12*12/100)=25.44%.
3rd year = 25.44+12+(12*25.55/100)=40.49%.
Then substitute the r value in simple interest for 1 year then you can get answer directly.
1st 2 year =a+b+(a*b/100)=12+12+(12*12/100)=25.44%.
3rd year = 25.44+12+(12*25.55/100)=40.49%.
Then substitute the r value in simple interest for 1 year then you can get answer directly.
(2)
Bhaskar chakrabarty said:
7 years ago
What will be the rate of compound interest if a man invests Rs. 1, 01, 490 and get Rs. 2, 03, 500 after 10 years?
Can anyone answer it?
Can anyone answer it?
(1)
BUDHLANI BADSHAH said:
7 years ago
@Amit.
Thank you for the best explanation.
Thank you for the best explanation.
Amit said:
8 years ago
12% = 12/100 = 3/25.
p = 25000.
Solve --- 25000x3/25 = 3000 first interest.
1st = 3000.
2nd = 3000 + 360. (3000x3/25=360).
3rd = 3000 + 360 + 360 + 43.20. (360x3/25=43.20).
--------------------------------------
9000+720+360+43.20 = 10123.20.
Its answer are exactly correct.
Sort and best math any Question solve in 15 second any problem.
p = 25000.
Solve --- 25000x3/25 = 3000 first interest.
1st = 3000.
2nd = 3000 + 360. (3000x3/25=360).
3rd = 3000 + 360 + 360 + 43.20. (360x3/25=43.20).
--------------------------------------
9000+720+360+43.20 = 10123.20.
Its answer are exactly correct.
Sort and best math any Question solve in 15 second any problem.
(8)
Ashish Jadhav said:
8 years ago
It is cross multiplication.
(1+12/100).
= (1*100+12)/100,
= (100+12)/100,
= 112/100,
= 28/25 i.e. divided by 4.
(1+12/100).
= (1*100+12)/100,
= (100+12)/100,
= 112/100,
= 28/25 i.e. divided by 4.
Ashish Jadhav said:
8 years ago
(1+12/100) = 1 * 100 + 12/100 = 100 + 12/100 = 112/100 = 28/25.
It is cross multiplication.
It is cross multiplication.
Sivasankari said:
8 years ago
@Muneer.
= 25000 * (1+12/100) => 250009112/100)^3.
= 25000(56/50)^3.
= 25000(28/25)^3.
And now expand the cube root we get 25000 * 28/25 * 28/25 * 28/25.
= 25000 * (1+12/100) => 250009112/100)^3.
= 25000(56/50)^3.
= 25000(28/25)^3.
And now expand the cube root we get 25000 * 28/25 * 28/25 * 28/25.
Sankari said:
8 years ago
Please explain how 28/25 came?
(2)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers