Verbal Reasoning - Series Completion - Discussion

Term 1 - 2, 2, 4, 6, 8, 10, ?
Term 2 - 1, 4, 5, 7, 8, 11, 13.

The missing number is in term 1 and also the path is first *1 and then adding +2 to the all alternatives so the missing number is 12.

And the answer is 12.

The answer should be 12.

Taking the difference between of every 1st and 4th term answer is 10.

Taking every 1st and 3rd number and calculating 2*0+2, 2*1+2, 2*2+2, 2*3+2, 2*4+2, 2*5+2 the answer is 12.

Let the number to find be x.

First write all the numbers in odd position:
2 2 4 6 8 10 x.

Numbers in Even position:
1 4 5 7 8 11.

As the x appears in even numbers list, we clearly get that x will be even.

So the x be either 10 or 12.

If you watch carefully, only even numbers appear twice, sometimes continuously. Sometimes having one number in between them.

Here, the first even number we have is 2.

2 1 2 -------- had one number in between.
Then, 4 4 ------continuously.
Then, 8 8 ------ continuously.

Then, we got 10 which is even number having one number in between, so the answer will be 10.

Ans is 10.

212
445
678
81011
101314

2 4 6 8 10 2's gap.
1 4 7 10 18 3's gap.
2 5 8 11 14 3's gap.

Yeah, it must be 12.

It should be 12.

Take alternative sequence 2, 2, 4, 6, 8, 10, so next term 12.

The 2 2 4 6 8 10 12.

The answer wll be 12.

Totally 13 terms are there , we should find the 13th term.(that's the question)

Term 1 = 2
Term 2 = 1
Term 3 = 2
Term 4 = 4
Term 5 = 4
Term 6 = 5
Term 7 = 6
Term 8 = 7
Term 9 = 8
Term 10 = 8
Term 11 = 10
Term 12 = 11
Term 13 = ?

Here they had given 12 known terms , so they can be equally split with 3 combination's like,

Combination No: 1) 1(2) 4(4) 7(6) 10(8) 13th term=(?)

Combination No: 2) 2(1) 5(4) 8(7) 11(10)

combination No: 3) 3(2) 6(5) 9(8) 12(11)

Therefore 13th term lies in the 1st combination and hence by analyzing it we come to an conclusion that all the term's are even number's , therefore the 13th term is 10.

How we will identifying there is 3 series is there?