Verbal Reasoning - Direction Sense Test - Discussion
Discussion Forum : Direction Sense Test - Direction Sense 1 (Q.No. 12)
12.
A man walks 2 km towards North. Then he turns to East and walks 10 km. After this he turns to North and walks 3 km. Again he turns towards East and walks 2 km. How far is he from the starting point?
Answer: Option
Explanation:
Discussion:
37 comments Page 4 of 4.
Subha said:
7 years ago
If we don't get a perfect square number like the square root of 533.
Then what will be the answer, Is this 23 or none of these?
Then what will be the answer, Is this 23 or none of these?
(1)
Irfana said:
7 years ago
Try making a big right-angled triangle from the Dia.
Now the base value will be 10+2 = 12 and the height will be 2+3= 5. Now use Pythagoras theorem. 5^2+ 12^2 . Hence answer.
Now the base value will be 10+2 = 12 and the height will be 2+3= 5. Now use Pythagoras theorem. 5^2+ 12^2 . Hence answer.
(6)
Singh said:
6 years ago
I can't understand this. Please explain me.
(2)
Viraj said:
5 years ago
Very nice explanation, Thanks @Nagendra Murthy.
(2)
Shivi said:
5 years ago
@All.
Let me explain it simply,
As in the answer pic (please see there) if we add the distances of AB and DC it would be 5 km(2+3) and the distances of BC and DE it would be 12km (10+2). Now, just extend AB and DE , we would get a point say F ( on their intersecting point). Now join A to E, we will get a right-angled triangle named triangle AFE.
Now by Pythagoras theorem, we will find out the line segment AE.
Hypotenuse^2= perpendicular^2 + base^2.
AE^2 = AF^2+ FE^2,
AE^2= 5^2 + 12^2,
AE^2= 25+144,
AE^2 = 169,
AE x AE= 13 x 13,
AE= 13.
So, 13 (option B) is the right answer.
Hope it helps
Let me explain it simply,
As in the answer pic (please see there) if we add the distances of AB and DC it would be 5 km(2+3) and the distances of BC and DE it would be 12km (10+2). Now, just extend AB and DE , we would get a point say F ( on their intersecting point). Now join A to E, we will get a right-angled triangle named triangle AFE.
Now by Pythagoras theorem, we will find out the line segment AE.
Hypotenuse^2= perpendicular^2 + base^2.
AE^2 = AF^2+ FE^2,
AE^2= 5^2 + 12^2,
AE^2= 25+144,
AE^2 = 169,
AE x AE= 13 x 13,
AE= 13.
So, 13 (option B) is the right answer.
Hope it helps
(52)
Gurwinder said:
4 years ago
Good, Thanks everyone for explaining the answer.
(2)
Manviya said:
4 years ago
How to solve this? Please explain me.
(12)
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