Six dice with upper faces erased are as shows.
The sum of the numbers of dots on the opposite face is 7.
|Ashok Kumar Nanda said: (Jul 27, 2013)|
|How any body can be sure of the dots of top faces of II IV AND VI are 1, 1 and 1. I didn't understand, if any body can help me I will be very grateful.|
|Anshu Goyal said: (May 9, 2014)|
|Consider dice 1 to 6 individually.
For (I), number opposite to 3 dots would be 4 dots (3+4=7), similarly number opposite to 6 dots would be 1 dot. Now, two faces are left ( Bottom and Top) and two numbers 2 and 5 are left (In a dice, there are 6 no.s 1,2,3,4,5,6). As given in the question, this (No. 1) is an odd numbered dice and the top face will contain odd number of dots (So 5 dots will be on the top).
Similarly, number of dots on the top face of the remaining 5 dices will be evaluated and at the end, sum of all six numbers on top faces of 6 dices would be the answer.
|Mustaq said: (Aug 31, 2017)|
|Does 12 and 3 have even numbers of that on their bomb on faces and the Das for 5th and 6th have a number of dots on the top faces then what will be the difference in the total number of top places between the two sets?|
|Kundan said: (Aug 31, 2018)|
|No of dots on the top faces of the dice (I) , (III) and (V) should be 1, 1 and 4 respectively as mentioned in the question.|
|Shubham said: (Nov 24, 2018)|
|The first statement itself says that opposite number form a sum of 7. So,
4 + 3 = 7,
2 + 5= 7 are the opposite sides.
So solving this, the answer is 14. Correct me if am wrong.
|Priyanka said: (Jun 8, 2020)|
|The Correct answer is 16.|
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