Verbal Reasoning - Dice - Discussion
Discussion Forum : Dice - Dice 2 (Q.No. 1)
Directions to Solve
Six dice with upper faces erased are as shows.
The sum of the numbers of dots on the opposite face is 7.
1.
If even numbered dice have even number of dots on their top faces, then what would be the total number of dots on the top faces of their dice?
Answer: Option
Explanation:
Even numbered dice are: (II), (IV) and (VI)
No. of dots on the top face of (II) dice = 6
No. of dots on the top face of (IV) dice = 6
and No. of dots on the top face of (VI) dice = 6
Therefore Required total = 6 + 6 + 6 = 18
Discussion:
33 comments Page 2 of 4.
Parul saroj said:
8 years ago
@ALL. Even number of dices are 2, 4, 6. It's clear that 2, 4, 5 are adjacent to each other. And it's said that top numbers should be even. Among 1 to 6, 2, 4, 6 are even, but 2 and 4 are adjacent. So, 6 is the answer.
(1)
Isaac said:
1 decade ago
When you observe carefully you see only 4, 5, 2, 3 will on the sides and the remaining two nos 6, 1 are left for us to deal with and amongh these two only 6 is even that explains every ones question.
Priyanka said:
7 years ago
There is no condition present saying only 6 to be taken as the number on the top of each, why can't we take either 2 are 4.
They are also the even numbers, please give a clear explanation for this.
They are also the even numbers, please give a clear explanation for this.
Nayeem khan said:
6 years ago
Why not consider 1st, 3rd and 5th dices? ist dice also have either 2 or 5, you can take 2 and similarly 2nd 3rd dices can also have on their top 2 and 4 respectively.
Please justify me.
Please justify me.
Prudhvi said:
2 decades ago
You told that even numbered dice have even number of dots on their top faces if we set it as four it should be 12 but you take it as 6.
Can we take 4 or not?
Can we take 4 or not?
Santhosh said:
8 years ago
As explained above all 6, except 5th are having 1 at the bottom. And all should have 6 at the top, but 1st dice is having 6 adjacent to 1.
Deepak Varshney said:
1 decade ago
I think so, ans is 10.
No. Of dots on dice II = 2.
No. Of dots on dice IV = 6 (as 4 and 2 at adjacent).
No. Of dots on dice VI = 2.
No. Of dots on dice II = 2.
No. Of dots on dice IV = 6 (as 4 and 2 at adjacent).
No. Of dots on dice VI = 2.
Shubham said:
3 years ago
Sum of opp. phases is =7.
Then,
Even number on the tip phase;
so,
6+1=7.
so,
I think that he takes 6.
Then,
Even number on the tip phase;
so,
6+1=7.
so,
I think that he takes 6.
(1)
Harsh said:
8 years ago
These are standerd dice and each nearest faces sum is not equal to 7 that's why we taking 6.
Arun said:
1 decade ago
I think 2 4 6 dice contain 9, 6, 9 dots so answer will be 24 I think once 0 through this.
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