Verbal Reasoning - Cube and Cuboid - Discussion
Discussion Forum : Cube and Cuboid - Cube and Cuboid 2 (Q.No. 1)
                   
                                       
                                  Directions to Solve
                   
                                    The following questions are based on the information given below:
- There is a cuboid whose dimensions are 4 x 3 x 3 cm.
 - The opposite faces of dimensions 4 x 3 are coloured yellow.
 - The opposite faces of other dimensions 4 x 3 are coloured red.
 - The opposite faces of dimensions 3 x 3 are coloured green.
 - Now the cuboid is cut into small cubes of side 1 cm.
 
1.
How many small cubes will have only two faces coloured ?
 
                                    Answer: Option
                                                    Explanation:
                                                
Number of small cubes having only two faces coloured = 6 from the front + 6 from the back + 2 from the left + 2 from the right
= 16
Discussion:
19 comments Page 2 of 2.
                
                        Vishal said: 
                         
                        1 decade ago
                
                2 cubes of green yellow face and 4 cubes of yellow red face.
                
                        Raghavan said: 
                         
                        1 decade ago
                
                Hi, refer the picture again. Note the Between the right side top cornor. The cube having 2 colored faces. Simultaneously bottom side cube having 2 colored faces. Thats why 2 came.
                
                        Raghavan said: 
                         
                        1 decade ago
                
                Could you tell me how does L-2*4 comes?
                
                        Prasanna said: 
                         
                        1 decade ago
                
                Thank you shekar.
                
                        Shekhar Ghate said: 
                         
                        1 decade ago
                
                The formula for cubes having two sides painted is
(L-2)x4 + (B-2)x4 + (H-2)x4 Where L = Length, B= Breadth, H=Height
In the above problem it is (4-2)x4 + (3-2)x4 + (3-2)x4
i.e 8 + 4 + 4 = 16
                (L-2)x4 + (B-2)x4 + (H-2)x4 Where L = Length, B= Breadth, H=Height
In the above problem it is (4-2)x4 + (3-2)x4 + (3-2)x4
i.e 8 + 4 + 4 = 16
                        Mrudula said: 
                         
                        1 decade ago
                
                Can some one explain this?
                
                        Sakthi said: 
                         
                        1 decade ago
                
                Could not understand how its two from left and right, hope its 3.
                
                        Narendra kirar said: 
                         
                        1 decade ago
                
                Please suggest any simple and shortcut answer.
                
                        Santosh said: 
                         
                        1 decade ago
                
                Please explain this problem.
                Post your comments here:
 
            
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