Verbal Reasoning - Cube and Cuboid - Discussion
Discussion Forum : Cube and Cuboid - Cube and Cuboid 2 (Q.No. 4)
Directions to Solve
The following questions are based on the information given below:
- There is a cuboid whose dimensions are 4 x 3 x 3 cm.
- The opposite faces of dimensions 4 x 3 are coloured yellow.
- The opposite faces of other dimensions 4 x 3 are coloured red.
- The opposite faces of dimensions 3 x 3 are coloured green.
- Now the cuboid is cut into small cubes of side 1 cm.
4.
How many small cubes will have only one face coloured ?
Answer: Option
Explanation:
Number of small cubes having only one face coloured = 2 x 2 + 2 x 2 + 2 x 1
= 4 + 4 + 2
= 10
Discussion:
9 comments Page 1 of 1.
Manish said:
6 months ago
Formula for cuboid or cube(in case of cube x,y,z same)
3 faces coloured = 8 ( corner).
2 faces coloured = (x-2)4+4(y-2)+4(z-2).
1 faces coloured = (x-2)(y-2)*2+(y-2)(z-2)*2+(z-2)(x-2)*2.
0 faces coloured =(x-2)(y-2)(z-2).
You can also optimise this formula.
3 faces coloured = 8 ( corner).
2 faces coloured = (x-2)4+4(y-2)+4(z-2).
1 faces coloured = (x-2)(y-2)*2+(y-2)(z-2)*2+(z-2)(x-2)*2.
0 faces coloured =(x-2)(y-2)(z-2).
You can also optimise this formula.
Mahesh said:
9 years ago
The new l,b,h is (L-2),(b-2),(h-2), then perform lb +bh+hl.
After that multiply by 2 for this question new l,b,h after subtracting it from 2 is, 2, 1, 2....2 * 1 + 1 * 1 + 1* 2 = 5 multiply it by two (5 * 2 = 10 ans).
After that multiply by 2 for this question new l,b,h after subtracting it from 2 is, 2, 1, 2....2 * 1 + 1 * 1 + 1* 2 = 5 multiply it by two (5 * 2 = 10 ans).
Alina said:
8 years ago
We can simplify it as;
5 [(l-2). (b-2) +(b-2). (h-2)+(h-2). (l-2)] .
*this formula is applied only if the small cube formed has its side as unity.
5 [(l-2). (b-2) +(b-2). (h-2)+(h-2). (l-2)] .
*this formula is applied only if the small cube formed has its side as unity.
Gaurav said:
1 decade ago
For red 2 from top and 2 from bottom.
For green 1 from side and 1 from backside.
For yellow 2 from front and 2 from back.
Therefore, 4+2+4=10.
For green 1 from side and 1 from backside.
For yellow 2 from front and 2 from back.
Therefore, 4+2+4=10.
Saurav Kumar said:
3 years ago
(2+2) yellow coloured
(2+2) red coloured.
(2+2) green coloured.
Hence, the answer is (4+4+4),
= 12.
(2+2) red coloured.
(2+2) green coloured.
Hence, the answer is (4+4+4),
= 12.
Sabiar said:
9 years ago
Anybody give me the actual formula to solve this problem.
Roshan said:
1 decade ago
Can someone explain it more clearly ?
(1)
Rahim said:
1 decade ago
Can we use any formula?
Dhana said:
1 decade ago
I did not understand.
(1)
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