Verbal Reasoning - Classification - Discussion

Discussion Forum : Classification - Section 13 (Q.No. 49)
Directions to Solve

In each of the following questions, some groups of letters are given, all of which, except one, share a common similarity while one is different. Choose the odd one out.


49.
Choose the odd one out.
AGZX
BDYW
EGVT
GITR
CEUS
Answer: Option
Explanation:

In all other groups, first and second as well as fourth and third letters are alternate. Also, the first and third letters occupy the same positions from the beginning and end of the alphabet respectively.

Discussion:
7 comments Page 1 of 1.

Surendra bhatta said:   3 years ago
I think A is the correct Answer.

Ritaban Pal said:   4 years ago
I think A is the correct Answer.

Ganesh said:   6 years ago
Right @Manoj Prabhakar.

Ganesh said:   6 years ago
I think option B is the correct answer.

Anil said:   7 years ago
I think option A is the correct answer.

Manoj Prabhakar said:   8 years ago
B can also be the Right answer because if we see in option B there are no vowels used but in rest of the options, at least one vowel is used.

Priyanka Roy Barman said:   10 years ago
I don't agree with option E as the answer. The write answer should be option A. In all the other options the first two letters are alternates as well as the last two letters. Only in option A the first two letters aren't alternates.

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