Verbal Reasoning - Character Puzzles - Discussion
Discussion Forum : Character Puzzles - Character Puzzles 1 (Q.No. 5)
5.
Which one will replace the question mark ?
Answer: Option
Explanation:
(15 x 2 - 3) = 27,
(31 x 2 - 6) = 56
and (45 x 2 - 9) = 81
Discussion:
17 comments Page 1 of 2.
Ronil said:
4 months ago
(3x1) = 3, (3x5) = 15, (3x9) = 27,
(6x1) = 6, (6X5) + 1 = 31, (6x9)+ 2 = 56,
(9x1) = 9, (9x5) = 45, (9x9) = 81.
Further, in sequence we will get (nx1)=n, (nx5)+1, (nx9)+2.
(6x1) = 6, (6X5) + 1 = 31, (6x9)+ 2 = 56,
(9x1) = 9, (9x5) = 45, (9x9) = 81.
Further, in sequence we will get (nx1)=n, (nx5)+1, (nx9)+2.
(1)
Abid mohammad said:
6 years ago
(15*2) -3=27.
(31*2) -6=56 //gap between these numbers (15 to 31) is 16.
(45*2) -9=81 //gap between these numbers (31 to 14) is 14.
(31*2) -6=56 //gap between these numbers (15 to 31) is 16.
(45*2) -9=81 //gap between these numbers (31 to 14) is 14.
Suresh said:
1 decade ago
step 1 : 1*3=3,5*3=15,9*3=27
step 2 : 1*6+0=6,5*6+1=31,9*6+2=56
step 3 : 1*9=9,5*9=45,9*9=81
step 2 : 1*6+0=6,5*6+1=31,9*6+2=56
step 3 : 1*9=9,5*9=45,9*9=81
MuraliKrishna Maddu said:
1 decade ago
3+12 = 15+12 = 27 -- -3,15,27.
6+25 =31+25 = 56 --- 6,31,56.
9+36 = 45+36 = 81 --- 9,45,81.
6+25 =31+25 = 56 --- 6,31,56.
9+36 = 45+36 = 81 --- 9,45,81.
NEERAJ SINGH GAIRA said:
1 decade ago
Logic is mid = (up+end)/2.
(3+27)/2 = 15.
(6+56)/2 = 31.
So (9+81)/2 = 45.
(3+27)/2 = 15.
(6+56)/2 = 31.
So (9+81)/2 = 45.
Raj said:
4 years ago
27+3 = 30, 30÷2 = 15.
56+6 = 62, 62÷2 = 31.
81+9 = 90, 90÷2 = 45.
56+6 = 62, 62÷2 = 31.
81+9 = 90, 90÷2 = 45.
(1)
Kiran said:
1 decade ago
step-1 27+3=30/2=15.
step-2 56+6=62/2=31.
step-3 9+81=90/2=45
step-2 56+6=62/2=31.
step-3 9+81=90/2=45
Tej Bahadur Budhathoki said:
5 years ago
15-3 = 12+15 = 27.
31-6 = 25+31 = 56.
45-9 = 36+45 = 81.
31-6 = 25+31 = 56.
45-9 = 36+45 = 81.
Kapil p said:
5 years ago
(27+3)÷2 = 15,
(56+6)÷2 = 31,
(81+9)÷2 = 45.
(56+6)÷2 = 31,
(81+9)÷2 = 45.
(1)
Nishant said:
7 years ago
(27+3)/2 = 15.
(56+6)/2 = 31.
(81+9)/2 = 45.
(56+6)/2 = 31.
(81+9)/2 = 45.
(2)
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