Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 7)
7.
A woman says, "If you reverse my own age, the figures represent my husband's age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum." The woman's age is
Answer: Option
Explanation:
Let x and y be the ten's and unit's digits respectively of the numeral denoting the woman's age.
Then, woman's age = (10X + y) years; husband's age = (10y + x) years.
Therefore (10y + x)- (10X + y) = (1/11) (10y + x + 10x + y)
(9y-9x) = (1/11)(11y + 11x) = (x + y) 10x = 8y x = (4/5)y
Clearly, y should be a single-digit multiple of 5, which is 5.
So, x = 4, y = 5.
Hence, woman's age = 10x + y = 45 years.
Discussion:
13 comments Page 2 of 2.
Atul Bhandare said:
1 decade ago
(x-y) = 1/11(x+y).
Check which age is satisfies this equation.
Option:C.
Check which age is satisfies this equation.
Option:C.
Viji said:
1 decade ago
Suppose take a answer 45.
Woman age is 45 so the husband age is reverse of wife so 54. Then the difference of the two ages is 9. See the problem one eleventh of their sum so the sum of the couple is 99.
That is 1/11*99=9
Both the answers are same(9).
So we conclude the 45 is the correct answer.
Woman age is 45 so the husband age is reverse of wife so 54. Then the difference of the two ages is 9. See the problem one eleventh of their sum so the sum of the couple is 99.
That is 1/11*99=9
Both the answers are same(9).
So we conclude the 45 is the correct answer.
Nikita said:
1 decade ago
Let x-y=x+y/11
11x-11y=x+y
10x=12y
5x=6y x:y=5:6
Womens age is multipal of 5
11x-11y=x+y
10x=12y
5x=6y x:y=5:6
Womens age is multipal of 5
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