Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 5)
5.
A, B, C, D and E play a game of cards. A says to B, "If you give me three cards, you will have as many as E has and if I give you three cards, you will have as many as D has." A and B together have 10 cards more than what D and E together have. If B has two cards more than what C has and the total number of cards be 133, how many cards does B have ?
Answer: Option
Explanation:
Clearly, we have :
B-3 = E ...(i)
B + 3 = D ...(ii)
A+B = D + E+10 ...(iii)
B = C + 2 ...(iv)
A+B + C + D + E= 133 ...(v)
From (i) and (ii), we have : 2 B = D + E ...(vi)
From (iii) and (vi), we have : A = B + 10 ...(vii)
Using (iv), (vi) and (vii) in (v), we get:
(B + 10) + B + (B - 2) + 2B = 133 
5B = 125 B = 25.
Discussion:
20 comments Page 2 of 2.
SHUDHI said:
9 years ago
How A + B = D + E + 10?
It must be D + E = A + B + 10.
It must be D + E = A + B + 10.
(1)
Lavanya said:
9 years ago
Please explain this clearly.
Raheem said:
9 years ago
n = 96.
=> 4n-4 = 96.
=> 4(n-1) = 96.
=> n-1 = 96/4.
=> n-1 = 24.
=> n = 24+1.
=> n = 25.
=> 4n-4 = 96.
=> 4(n-1) = 96.
=> n-1 = 96/4.
=> n-1 = 24.
=> n = 24+1.
=> n = 25.
NEHA said:
1 decade ago
A+B+C+D+E = 133.
B+3 = D(1).
B-3 = E(2).
B = C+2, C = B-2(3).
A+B = D+E+10 = (B+3)+(B-3)+10(4).
From 1, 2, 3 & 4.
We get...
B+3+B-3+10+B-2+B+3+B-3 = 133.
5B+8 = 133.
5B = 125.
B = 25.
B+3 = D(1).
B-3 = E(2).
B = C+2, C = B-2(3).
A+B = D+E+10 = (B+3)+(B-3)+10(4).
From 1, 2, 3 & 4.
We get...
B+3+B-3+10+B-2+B+3+B-3 = 133.
5B+8 = 133.
5B = 125.
B = 25.
Nikolas said:
1 decade ago
We have,
B - 3 = E .
B + 3 = D.
B=C+2=>C=B-2.
Then,
A+B = D + E+10.
Which we can be done into,
A+B = B-3 + B+3 + 10.
A+B= 2B + 10.
Then lets add all.
A+B+C+D+E=133.
2B+10+B-2+B+3+B-3=133.
5B=133-8.
B=125/5.
B=25 -> we get the answer.
B - 3 = E .
B + 3 = D.
B=C+2=>C=B-2.
Then,
A+B = D + E+10.
Which we can be done into,
A+B = B-3 + B+3 + 10.
A+B= 2B + 10.
Then lets add all.
A+B+C+D+E=133.
2B+10+B-2+B+3+B-3=133.
5B=133-8.
B=125/5.
B=25 -> we get the answer.
Bidya said:
1 decade ago
What was the day on 100 November 1581 please give me solve?
Marcos said:
1 decade ago
How do you get from,
B-3 = E.
B+3 = D.
to
2B = D+E.
Do you just add them together?
B-3 = E.
B+3 = D.
to
2B = D+E.
Do you just add them together?
Archana Santhosh said:
1 decade ago
A+B+C+D+E=133
(B+10)+B+(B-2)+2B=133
5B+8(i.e 10-2)=133
5B=133-8
5B=125
B=125/5
B=25.
(B+10)+B+(B-2)+2B=133
5B+8(i.e 10-2)=133
5B=133-8
5B=125
B=125/5
B=25.
Archana said:
1 decade ago
B=C+2=>C=B-2
2B=D+E=>D=2B-E
(B+10)+B+(B-2)+2B-E+E=133
B+10+B+B-2+2B=133
5B+8=133
5B=133-8
B=125/5
B=25
2B=D+E=>D=2B-E
(B+10)+B+(B-2)+2B-E+E=133
B+10+B+B-2+2B=133
5B+8=133
5B=133-8
B=125/5
B=25
Ashutosh said:
1 decade ago
Explain me the last 2 lines.
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