Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 3)
3.
An institute organised a fete and 1/5 of the girls and 1/8 of the boys participated in the same. What fraction of the total number of students took part in the fete ?
Discussion:
82 comments Page 8 of 9.
Dinesh Choudhary said:
1 decade ago
Answer:
Boys participation = 20%.
Girls participation = 12.5%.
Total participation = 32.5% = 32.5/100 = 13/40.
Boys participation = 20%.
Girls participation = 12.5%.
Total participation = 32.5% = 32.5/100 = 13/40.
Aroon Kumar said:
1 decade ago
Given data.
1/5 of girls, let girls be 'a'.
1/8 of boys, boys be b'.
Participated from an institute in same.
That means let the total no of students in institute be 'x'.
Such that according to given data sum of boys n girls = x.
i.e. , a/5+b/8 = x.
=>8a+5b = 40x.
If the fraction is required then x = (8a+5b) /40.
So I agree with 'C'.
1/5 of girls, let girls be 'a'.
1/8 of boys, boys be b'.
Participated from an institute in same.
That means let the total no of students in institute be 'x'.
Such that according to given data sum of boys n girls = x.
i.e. , a/5+b/8 = x.
=>8a+5b = 40x.
If the fraction is required then x = (8a+5b) /40.
So I agree with 'C'.
Udas Bugti said:
9 years ago
According to me answer is :
Girls participated = 1/5.
Boys participated = 1/8.
It's very simple, it just asking about the total num of participated student,but not 4 total students.
So, 1/5 + 1/8 = 13/40.
The correct answer is 13/40.
If they asked about total students then the correct answer is inadequate.
Girls participated = 1/5.
Boys participated = 1/8.
It's very simple, it just asking about the total num of participated student,but not 4 total students.
So, 1/5 + 1/8 = 13/40.
The correct answer is 13/40.
If they asked about total students then the correct answer is inadequate.
Dhananjay Singh said:
1 decade ago
@Sneha.
I love the way you added %age of boys and %age of girls to find out the total %age of participation. As per your logic if total boys and total girls participate the fete then total participation will turn to 200% just a minor increase of 100%.
I love the way you added %age of boys and %age of girls to find out the total %age of participation. As per your logic if total boys and total girls participate the fete then total participation will turn to 200% just a minor increase of 100%.
RISHI KUMAR DUBEY said:
1 decade ago
Let us consider that 1/5 girls are participating. That means overall 20% of girls are participating.
Similarly 1/8 boys are participating that means out of 100% only 12.5% boys are participating.
Total 12.5+20 = 32.5% candidate are participating out of 100% student than 32.
5/100 = 13/14 student are participating.
Answer is 13/14.
And I am sure about that.
Similarly 1/8 boys are participating that means out of 100% only 12.5% boys are participating.
Total 12.5+20 = 32.5% candidate are participating out of 100% student than 32.
5/100 = 13/14 student are participating.
Answer is 13/14.
And I am sure about that.
Anum said:
1 decade ago
2/13 is good answer because he talked about two groups and said find total simple add 2 group and there sum is 2/13.
Ashwin said:
1 decade ago
Take total boys as 10 and total girls as 16 for easier calculation. So total strength is 26.
Calculate ratio of boys and girls participated and add them. And find fraction to 26.
You will get 2/13.
Calculate ratio of boys and girls participated and add them. And find fraction to 26.
You will get 2/13.
G.priyanka said:
1 decade ago
There is no saying of the total numbers of students. So the answer is C, there is inadequate information.
Devi said:
1 decade ago
According to the fraction point my answer is 13/40 but there is no particular information about students so the C is answer.
Vanessa said:
1 decade ago
There is no saying of the total number of students, so the answer is C, there is inadequate information.
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