Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 3)
3.
An institute organised a fete and 1/5 of the girls and 1/8 of the boys participated in the same. What fraction of the total number of students took part in the fete ?
Discussion:
81 comments Page 7 of 9.
Lokesh said:
1 decade ago
We can't write the human's in fraction.
Jim said:
1 decade ago
LCM method cannot be used here. The fractions are given for different genders. So LCM cannot be taken.
And Sneha, percentages can never be added.
Suppose they had given 4/5 of girls and 7/8 of boys participated. Would you add 80% and 87.5% and say 167.5% of the students attended? PERCENTAGES CANNOT BE ADDED.
And Sneha, percentages can never be added.
Suppose they had given 4/5 of girls and 7/8 of boys participated. Would you add 80% and 87.5% and say 167.5% of the students attended? PERCENTAGES CANNOT BE ADDED.
Sneha said:
1 decade ago
1/5 of girls i.e 20% of girls participated.
1/8 of boys i.e 12.5% of boys participated.
Total participation = 20+12.5= 32.5% i.e 13/40.
1/8 of boys i.e 12.5% of boys participated.
Total participation = 20+12.5= 32.5% i.e 13/40.
SAGILI RAMANAREDDY said:
1 decade ago
Suggest me if this logic is wrong:
If X is the boys and Y is girls ,and also given 1/5 of boys and 1/8 of girls. Here but not given total number of students participated in that fete
(1/5)x+(1/8)y=? So I think answer is "C".
If X is the boys and Y is girls ,and also given 1/5 of boys and 1/8 of girls. Here but not given total number of students participated in that fete
(1/5)x+(1/8)y=? So I think answer is "C".
Jitendra said:
1 decade ago
Data Inadequate. Because it is said that 1/5 of the girls and i/8 of the boys. Here no clue available to find the total number of students. If LCM is when found it would be 40. but this 40 is not the total of students.
As 1/5 of girls = 8/40 of girls, here 40 is only total number of girls not the total number of students. The same way 1/8 of boys = 5/40 of boys. so the total number of boys and girls is 40+40=80.
The total number of boys and girls participated is 8+5=13. therefore desirable fraction as Hari thinks it to be 13/40 is 13/80.
13/80 is also not correct as total number of boys and girls cannot be found as some clues like ratio of the number of boys to that of girls is missing.
As 1/5 of girls = 8/40 of girls, here 40 is only total number of girls not the total number of students. The same way 1/8 of boys = 5/40 of boys. so the total number of boys and girls is 40+40=80.
The total number of boys and girls participated is 8+5=13. therefore desirable fraction as Hari thinks it to be 13/40 is 13/80.
13/80 is also not correct as total number of boys and girls cannot be found as some clues like ratio of the number of boys to that of girls is missing.
Hari said:
1 decade ago
According to me answer is 13/40.
Sachin said:
1 decade ago
Siddique's method of taking LCM and getting the total number is correct. I have seen in many forums of this kind of strategy especially.
Siddique said:
1 decade ago
According to me,
Let a=1/5 b=1/8
LCM =40.
a=1/5*8/8=8/40.
b=1/8*5/5=5/40.
= 8/40+5/40 = 13/40.
Let a=1/5 b=1/8
LCM =40.
a=1/5*8/8=8/40.
b=1/8*5/5=5/40.
= 8/40+5/40 = 13/40.
Kannan said:
1 decade ago
Out of 5 girls one girl participated, out of 8 boys one boy participated. so out of 13 students 2 students participated.
Therefore ans is 2/13.
Therefore ans is 2/13.
Rajiv said:
1 decade ago
Manika, Harshita the Answer is "Data Inadequate", because for answer to be correct, it has to be true for all values. But here it changes with values. Option A. Total girls 5, Total Boys 8, answer is 2/13, but Option B, 5 girls and 16 boys, it comes 3/21 which is equivalent to 2/14 (completely diff. from 2/13 derived earlier.
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