Verbal Reasoning - Arithmetic Reasoning - Discussion

All of the above do not address the fact that the boys and girls of the "institute" may include non "students" or adults if "boy" and "girls" is meant to distinguish from non-juvenile students. Sloppy questions can often lead to ambiguities and so many answers.

1/5*8/8=8/40 ---- 1/8*5/5=5/40 $$ 5/40+8/40=13/40 (this formula is called fraction by inspection). Basic maths.

If we do view this as an LDM problem, then 13/40 would be correct.

1/5 girls = 8/40 girls.
= 13/40 total.
1/8 boys = 5/40 boys.

If 13/40 was correct, then the decimal. 325(13 divided by 40) when applied to any class size would provide the correct answer.

We know for a fact that:

= 1/5 girls.
= 2 children of 13 total.
= 1/8 boys.
= 13*0.325 = 4.225.

This conclusion is contrary to what we know to be true.

Therefore without knowing the total number of girls in the class and the total number of boys, it is impossible to determine an absolute fraction.

I agree with option B.

Because here the no. of girls are participated is 1/5.

And no. of boys are participated is 1/8.

And here ask what is the fraction of students that are participated.

So, 1/5+1/8 is equal to 13/40.

By taking L.C.M. of 1/5+1/8.

Let number of boys be 80 and numbers of girls be 50.

Therefore, total number of students = 80 + 50 = 130.

Number of boys who participated in fete = 1/8*80 = 10.

Number of girls who participated in fete = 1/5*50 = 10.

Therefore, total numbers of students who participated in fete = 20.

Hence, the fraction of students participating in fete = 20/130 = 2/13.

So the answer is option A.

1/8+1/5=13/40.

Boys participation = 1/8.

Girls participation = 1/5.

According to 1/8+1/5.

13/40 answer.

Answer:

Boys participation = 20%.

Girls participation = 12.5%.

Total participation = 32.5% = 32.5/100 = 13/40.

Given data.

1/5 of girls, let girls be 'a'.
1/8 of boys, boys be b'.

Participated from an institute in same.

That means let the total no of students in institute be 'x'.

Such that according to given data sum of boys n girls = x.

i.e. , a/5+b/8 = x.

=>8a+5b = 40x.

If the fraction is required then x = (8a+5b) /40.

So I agree with 'C'.

My answer is different because,

Let total is x.

x/5+x/8 = 13x/40 taken LCM. But we want fraction.

So, x/13x/40 = 40/13.

My answer is none of these.