Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 3)
3.
An institute organised a fete and 1/5 of the girls and 1/8 of the boys participated in the same. What fraction of the total number of students took part in the fete ?
Discussion:
83 comments Page 3 of 9.
Manikandan said:
9 years ago
You are correct @Manika.
Shabir Ali Shah said:
8 years ago
According to my opinion, it should be 13/40.
B/C 1/5+1/8=x
==> 5+8/40=x.
Hence 13/40 is the right answer.
B/C 1/5+1/8=x
==> 5+8/40=x.
Hence 13/40 is the right answer.
Rekha said:
9 years ago
According to me, option a is correct.
Syamily said:
9 years ago
I think 1/5 + 1/8 (cross multiplication) = 8 + 5/40 = 13/40.
Phoenix said:
9 years ago
Can anyone tell me how could we know the fraction by having ratio of girls to ratio of boys?
Atul said:
9 years ago
Yeah, data inadequate. According to me. There should be a ratio of No of girls and No of boys.
Gangadhri said:
10 years ago
The correct answer is 2/12 because the total no of girls = 5, participated girls = 1 and total no of boys = 8 participated boys = 1.
So total no of students = 13 particepated students= 2.
Then by the fraction it is = 2/13.
So total no of students = 13 particepated students= 2.
Then by the fraction it is = 2/13.
Vishal said:
10 years ago
I think the answer is 13/40 because according to my options:
1/5 + 1/8 = 13/40.
Then, how the answer should be Data not adequate?
1/5 + 1/8 = 13/40.
Then, how the answer should be Data not adequate?
Nalinikanta said:
10 years ago
According to the question, we are not informed regarding the total no of students.
So, let total no of students = x.
No of girls participated = x/5
No of boys participated = x/6
So, total no of students participated = 13x/40, then a fraction of the original number of students obtained = 13x/40 * 1/x = 13/40.
So, let total no of students = x.
No of girls participated = x/5
No of boys participated = x/6
So, total no of students participated = 13x/40, then a fraction of the original number of students obtained = 13x/40 * 1/x = 13/40.
Dhanesh said:
9 years ago
Yes, you are correct @Parusharam.
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