Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 3)
3.
An institute organised a fete and 1/5 of the girls and 1/8 of the boys participated in the same. What fraction of the total number of students took part in the fete ?
Discussion:
81 comments Page 3 of 9.
Lokesh said:
1 decade ago
We can't write the human's in fraction.
GOTKHAR said:
1 decade ago
1/5 + 1/8 = 13/40 ratio is correct.
2/10 + 2/16 = 13/40 ratio is coming same.
3/15 + 3/24 = 13/40 ratio is again coming same.
1/x + 1/y = (x+y) /xy.
As 5 and 8 are co-primes.
400 students participated then 130 students participated.
800 students then 260 students participated.
There fore the answer 13/40 is correct as the total students fraction is asked not the ratio of the girls and boys is asked.
(we can distinguish girls and boys numbers separately from this question, that's all).
{this is just like asking; "2 bench and 3 desk together costing 100Rs, then 3 bench and 5 desk costing how much = 160}.
2/10 + 2/16 = 13/40 ratio is coming same.
3/15 + 3/24 = 13/40 ratio is again coming same.
1/x + 1/y = (x+y) /xy.
As 5 and 8 are co-primes.
400 students participated then 130 students participated.
800 students then 260 students participated.
There fore the answer 13/40 is correct as the total students fraction is asked not the ratio of the girls and boys is asked.
(we can distinguish girls and boys numbers separately from this question, that's all).
{this is just like asking; "2 bench and 3 desk together costing 100Rs, then 3 bench and 5 desk costing how much = 160}.
Vaibhav said:
1 decade ago
What fraction ?
(1/5)+(1/8) = 8+5/5*8 = 13/40.
This is correct answer if only asked to find fraction.
(1/5)+(1/8) = 8+5/5*8 = 13/40.
This is correct answer if only asked to find fraction.
Bhavana said:
1 decade ago
Here its given 1/5th of girls and 1/8th of boys.
If we consider (girls, boys) = (5, 8) or (10, 16) so on. We can get our answer as 2/13. But if someone considers (girls, boys) = (15, 16) we get our answer as 5/31.
So by this we cannot blindly decide the strength of boys and girls. Therefore we can opt for Option 'C' i.e., data inadequate'.
If we consider (girls, boys) = (5, 8) or (10, 16) so on. We can get our answer as 2/13. But if someone considers (girls, boys) = (15, 16) we get our answer as 5/31.
So by this we cannot blindly decide the strength of boys and girls. Therefore we can opt for Option 'C' i.e., data inadequate'.
Vanessa said:
1 decade ago
There is no saying of the total number of students, so the answer is C, there is inadequate information.
Devi said:
1 decade ago
According to the fraction point my answer is 13/40 but there is no particular information about students so the C is answer.
G.priyanka said:
1 decade ago
There is no saying of the total numbers of students. So the answer is C, there is inadequate information.
Ashwin said:
1 decade ago
Take total boys as 10 and total girls as 16 for easier calculation. So total strength is 26.
Calculate ratio of boys and girls participated and add them. And find fraction to 26.
You will get 2/13.
Calculate ratio of boys and girls participated and add them. And find fraction to 26.
You will get 2/13.
Anum said:
1 decade ago
2/13 is good answer because he talked about two groups and said find total simple add 2 group and there sum is 2/13.
RISHI KUMAR DUBEY said:
1 decade ago
Let us consider that 1/5 girls are participating. That means overall 20% of girls are participating.
Similarly 1/8 boys are participating that means out of 100% only 12.5% boys are participating.
Total 12.5+20 = 32.5% candidate are participating out of 100% student than 32.
5/100 = 13/14 student are participating.
Answer is 13/14.
And I am sure about that.
Similarly 1/8 boys are participating that means out of 100% only 12.5% boys are participating.
Total 12.5+20 = 32.5% candidate are participating out of 100% student than 32.
5/100 = 13/14 student are participating.
Answer is 13/14.
And I am sure about that.
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