Verbal Reasoning - Arithmetic Reasoning - Discussion
Discussion Forum : Arithmetic Reasoning - Section 1 (Q.No. 3)
3.
An institute organised a fete and 1/5 of the girls and 1/8 of the boys participated in the same. What fraction of the total number of students took part in the fete ?
Discussion:
81 comments Page 3 of 9.
Devansh said:
8 years ago
Let the total no of students be x.
x=x/8+x/5.
=5x/40+8x/40.
x=13x\40.
No of student = 13/40(as x will be cancel from both side).
x=x/8+x/5.
=5x/40+8x/40.
x=13x\40.
No of student = 13/40(as x will be cancel from both side).
Bin Yamin said:
8 years ago
Let total number of girls in the institute=x.
Total number of boys=y.
Now,
Girls participate 1/5 of x and boys participate 1/8 of y
Which becomes
x/5+y/8.
8x+5y/40 is correct answer.
which is not found in the given answer.
Therefore inadequate.
Total number of boys=y.
Now,
Girls participate 1/5 of x and boys participate 1/8 of y
Which becomes
x/5+y/8.
8x+5y/40 is correct answer.
which is not found in the given answer.
Therefore inadequate.
Lilyana said:
8 years ago
Yes, I agree @Manika.
Joshua said:
9 years ago
According to me, the answer is 13/40.
Dhanesh said:
9 years ago
Yes, you are correct @Parusharam.
Amit chetry said:
9 years ago
I think you are correct @Malay.
Manikandan said:
9 years ago
You are correct @Manika.
Parusharam said:
9 years ago
My option also 13/40. If we see the percentage based.
Anil said:
9 years ago
1/5& 1/8.
Lcm 40 and 8 + 5 = 13 then the answer is 13/40.
Lcm 40 and 8 + 5 = 13 then the answer is 13/40.
Puja patil said:
9 years ago
According to the given question.
Consider x = total no of fete.
Girls = 1/5,
Boys = 1/8,
x = 1/5 + 1/8,
x = 8 + 5/40,
x = 40.
Consider x = total no of fete.
Girls = 1/5,
Boys = 1/8,
x = 1/5 + 1/8,
x = 8 + 5/40,
x = 40.
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