Online Electronics and Communication Engineering Test - Automatic Control Systems Test
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- Total number of questions: 20.
- Time allotted: 30 minutes.
- Each question carries 1 mark; there are no negative marks.
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Marks : 2/20
Test Review : View answers and explanation for this test.

Transfer function = (G1 + 1) G2 + 1 = G1 G2 + G2 + 1.

The magnitudes A and G(jω) are multiplied and phase angles are added.

Since there are two sign changes in the first column, hence two roots in right half plane.


For the inner loop, transfer function =
Then .

The maximum phase lead is given by
In this case a = 1/3. Hence sin Φm = = 0.5 or Φm = 30°.

It does not become real at any frequency.
See transfer function in the equation .


Assertion (A): For a given system only one of the static error constants is finite and significant.
Reason (R): If finite static error constant is large, the loop gain becomes smaller as ω approaches zero.

- a pair of potentiometers
- a pair of synchros
- a differential transformer
- a metadyne
- a control transformer
Assertion (A): If points at infinity are included, G(s) has same number of poles and zeros.
Reason (R): The function has a zero at s = - 2.