Online C Programming Test - C Programming Test 1
- This is a FREE online test. Beware of scammers who ask for money to attend this test.
- Total number of questions: 20.
- Time allotted: 30 minutes.
- Each question carries 1 mark; there are no negative marks.
- DO NOT refresh the page.
- All the best!
Marks : 2/20
Test Review : View answers and explanation for this test.
#include<stdio.h>
int main()
{
int x = 10, y = 100%90, i;
for(i=1; i<10; i++)
if(x != y);
printf("x = %d y = %d\n", x, y);
return 0;
}
| 1 : | The printf() function is called 10 times. |
| 2 : | The program will produce the output x = 10 y = 10 |
| 3 : | The ; after the if(x!=y) will NOT produce an error. |
| 4 : | The program will not produce output. |
#include<stdio.h>
int main()
{
int k, num=30;
k = (num>5 ? (num <=10 ? 100 : 200): 500);
printf("%d\n", num);
return 0;
}
Step 1: int k, num=30; here variable k and num are declared as an integer type and variable num is initialized to '30'.
Step 2: k = (num>5 ? (num <=10 ? 100 : 200): 500); This statement does not affect the output of the program. Because we are going to print the variable num in the next statement. So, we skip this statement.
Step 3: printf("%d\n", num); It prints the value of variable num '30'
Step 3: Hence the output of the program is '30'
#include<stdio.h>
int main()
{
struct emp
{
char name[20];
float sal;
};
struct emp e[10];
int i;
for(i=0; i<=9; i++)
scanf("%s %f", e[i].name, &e[i].sal);
return 0;
}
Compile and Run the above program in Turbo C:
C:\>myprogram.exe Sundar 2555.50 scanf : floating point formats not linked Abnormal program termination
The program terminates abnormally at the time of entering the float value for e[i].sal.
Solution:
Just add the following function in your program. It will force the compiler to include required libraries for handling floating point linkages.
static void force_fpf() /* A dummy function */
{
float x, *y; /* Just declares two variables */
y = &x; /* Forces linkage of FP formats */
x = *y; /* Suppress warning message about x */
}The keyword return is used to transfer control from a function back to the calling function.
Example:
#include<stdio.h>
int add(int, int); /* Function prototype */
int main()
{
int a = 4, b = 3, c;
c = add(a, b);
printf("c = %d\n", c);
return 0;
}
int add(int a, int b)
{
/* returns the value and control back to main() function */
return (a+b);
}
Output:
c = 7
long fun(int num)
{
int i;
long f=1;
for(i=1; i<=num; i++)
f = f * i;
return f;
}
Yes, this function calculates and return the factorial value of an given integer num.
#include<stdio.h>
int main()
{
float a=3.14;
char *j;
j = (char*)&a;
printf("%d\n", *j);
return 0;
}
#include<stdio.h>
int main()
{
int a=10, *j;
void *k;
j=k=&a;
j++;
k++;
printf("%u %u\n", j, k);
return 0;
}
Error in statement k++. We cannot perform arithmetic on void pointers.
The following error will be displayed while compiling above program in TurboC.
Compiling PROGRAM.C:
Error PROGRAM.C 8: Size of the type is unknown or zero.
| 1: | The array int num[26]; can store 26 elements. |
| 2: | The expression num[1] designates the very first element in the array. |
| 3: | It is necessary to initialize the array at the time of declaration. |
| 4: | The declaration num[SIZE] is allowed if SIZE is a macro. |
1. The array int num[26]; can store 26 elements. This statement is true.
2. The expression num[1] designates the very first element in the array. This statement is false, because it designates the second element of the array.
3. It is necessary to initialize the array at the time of declaration. This statement is false.
4. The declaration num[SIZE] is allowed if SIZE is a macro. This statement is true, because the MACRO just replaces the symbol SIZE with given value.
Hence the statements '1' and '4' are correct statements.
Declaration: char *strrchr(const char *s, int c);
It scans a string s in the reverse direction, looking for a specific character c.
Example:
#include <string.h>
#include <stdio.h>
int main(void)
{
char text[] = "I learn through IndiaBIX.com";
char *ptr, c = 'i';
ptr = strrchr(text, c);
if (ptr)
printf("The position of '%c' is: %d\n", c, ptr-text);
else
printf("The character was not found\n");
return 0;
}
Output:
The position of 'i' is: 19
#include<stdio.h>
int main()
{
char ch = 'A';
printf("%d, %d, %d", sizeof(ch), sizeof('A'), sizeof(3.14f));
return 0;
}
Step 1: char ch = 'A'; The variable ch is declared as an character type and initialized with value 'A'.
Step 2:
printf("%d, %d, %d", sizeof(ch), sizeof('A'), sizeof(3.14));
The sizeof function returns the size of the given expression.
sizeof(ch) becomes sizeof(char). The size of char is 1 byte.
sizeof('A') becomes sizeof(65). The size of int is 4 bytes (as mentioned in the question).
sizeof(3.14f). The size of float is 4 bytes.
Hence the output of the program is 1, 4, 4
#include<stdio.h>
int main()
{
char str[] = "Nagpur";
str[0]='K';
printf("%s, ", str);
str = "Kanpur";
printf("%s", str+1);
return 0;
}
The statement str = "Kanpur"; generates the LVALUE required error. We have to use strcpy function to copy a string.
To remove error we have to change this statement str = "Kanpur"; to strcpy(str, "Kanpur");
The program prints the string "anpur"
#include<stdio.h>
int main()
{
int i=4, j=8;
printf("%d, %d, %d\n", i|j&j|i, i|j&j|i, i^j);
return 0;
}
The following is the example program to explain "using bit fields inside an union".
#include<stdio.h>
union Point
{
unsigned int x:4;
unsigned int y:4;
int res;
};
int main()
{
union Point pt;
pt.x = 2;
pt.y = 3;
pt.res = pt.y;
printf("\n The value of res = %d" , pt.res);
return 0;
}
// Output: The value of res = 3
#include<stdio.h>
int main()
{
FILE *fp;
char ch;
int i=1;
fp = fopen("myfile.c", "r");
while((ch=getc(fp))!=EOF)
{
if(ch == '\n')
i++;
}
fclose(fp);
return 0;
}
This program counts the number of lines in the file myfile.c by counting the character '\n' in that file.
#include<stdio.h>
int main()
{
char c=48;
int i, mask=01;
for(i=1; i<=5; i++)
{
printf("%c", c|mask);
mask = mask<<1;
}
return 0;
}
typedef struct data;
{
int x;
sdata *b;
}sdata;
#include<stdio.h>
#include<stdarg.h>
void varfun(int n, ...);
int main()
{
varfun(3, 7, -11.2, 0.66);
return 0;
}
void varfun(int n, ...)
{
float *ptr;
int num;
va_start(ptr, n);
num = va_arg(ptr, int);
printf("%d", num);
}