C Programming - Control Instructions - Discussion

Good explanation @Kavya.

Thanks @Kavya.

@All.

According to me, it is;

#include<stdio.h>
int main()
{
int x = 10, y = 100%90, i;
/* (i) Intialize x with the value of 10
(ii) Intialize y with the value of 10 [ 100%90 = 10 (% returns remainder)]
(iii) declare i
for(i=1; i<10; i++)
/* There is no relation between for loop and if condition */
if(x != y);
/* (i) [ 10 !=10 ] , the condition is false but
(ii) ";" (semicolon) has terminated the statement and moves to next statement.. */
printf("x = %d y = %d\n", x, y);
/* (i) x, y is assigned the value 10 which has been initialized earlier */
return 0;
}

Explain it, please.

Thank you, for explaining this program.

Thank you, @Prasanth.

When this statement executes why = 100% 90 the why value become 10, the loop continue 9 times and the value of if either true or false it's no matter because there is a semicolon after that that means the if end there then it comes to the printf statement and print the x value as 10 and why value as 10; so option B is the correct answer. I agree but how print output 2, 3 please explain someone.

@Kavya.

Your explanation is clear and useful. Thank you.

I don't now after if condition put semicolon in C you clearly explain.

Program successfully compile and execute.

It produce output: x = 10; y = 10 for 9 times.