Non Verbal Reasoning - Analytical Reasoning - Discussion
Discussion Forum : Analytical Reasoning - Section 1 (Q.No. 1)
1.
Find the number of triangles in the given figure.
Answer: Option
Explanation:
The figure may be labelled as shown.
The simplest triangles are AHG, AIG, AIB, JFE, CJE and CED i.e. 6 in number.
The triangles composed of two components each are ABG, CFE, ACJ and EGI i.e. 4 in number.
The triangles composed of three components each are ACE, AGE and CFD i.e. 3 in number.
There is only one triangle i.e. AHE composed of four components.
Therefore, There are 6 + 4 + 3 + 1 = 14 triangles in the given figure.
Discussion:
53 comments Page 5 of 6.
Namrata said:
8 years ago
Nice explanation @Priyanka.
But is it applicable on any other diagram? Like on square or rectangle?
But is it applicable on any other diagram? Like on square or rectangle?
(1)
B. Surya kumar peetha said:
8 years ago
CFD is covered by 4 triangles. This changes the calculation by triangles covered by three components are 2 and four triangle components 2.
(1)
Chithra said:
7 years ago
@ Shalini.
Thank you for your explanation. It is easier to understand.
Thank you for your explanation. It is easier to understand.
(1)
Mahesh said:
7 years ago
The formula is;
No of nodes+2(no of inner nodes).
No of nodes+2(no of inner nodes).
(3)
Indhumathi said:
7 years ago
Nice, thanks @Priyanka.
(1)
SANTHOSH said:
7 years ago
Nice shortcut, thank you @Priyanka.
Swati said:
7 years ago
Thanks @Priyanka.
(1)
Madhuri said:
6 years ago
The easiest way is to pick an edge at a time from the boundary like AH and count the no. Of triangles having it as one of its sides. These are AHG and AHE.
Then take up the next edge, say AC and count the no of triangles formed with it. These are ACE and ACJ.
Similarly, for GE the triangles are GEA and GEI.
For AG, we have AGB, AGI
For CE, we have, CEJ, CEF
For CD, it is CDE and CDF
Besides these, there are ABI, EFJ.
No more triangles are there. And the counting has reached 14.
The way to confirm that no triangles are left uncounted is to pick the edges one by one in a cyclic manner that is to start from a vertex and keep on moving from it in a certain direction along the boundary of the given figure.
Then take up the next edge, say AC and count the no of triangles formed with it. These are ACE and ACJ.
Similarly, for GE the triangles are GEA and GEI.
For AG, we have AGB, AGI
For CE, we have, CEJ, CEF
For CD, it is CDE and CDF
Besides these, there are ABI, EFJ.
No more triangles are there. And the counting has reached 14.
The way to confirm that no triangles are left uncounted is to pick the edges one by one in a cyclic manner that is to start from a vertex and keep on moving from it in a certain direction along the boundary of the given figure.
(5)
Diya said:
5 years ago
Thanks @Priyanka.
(4)
Muhammad Ibad ALi said:
4 years ago
Components mean that how many sections the triangle is divided.
(4)
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