Networking - Subnetting - Discussion

Discussion Forum : Subnetting - Subnetting (Q.No. 1)
1.
Your router has the following IP address on Ethernet0: 172.16.2.1/23. Which of the following can be valid host IDs on the LAN interface attached to the router?
  1. 172.16.1.100
  2. 172.16.1.198
  3. 172.16.2.255
  4. 172.16.3.0
1 only
2 and 3 only
3 and 4 only
None of the above
Answer: Option
Explanation:
The router's IP address on the E0 interface is 172.16.2.1/23, which is 255.255.254.0. This makes the third octet a block size of 2. The router's interface is in the 2.0 subnet, and the broadcast address is 3.255 because the next subnet is 4.0. The valid host range is 2.1 through 3.254. The router is using the first valid host address in the range.
Discussion:
35 comments Page 2 of 4.

Mohamad Fazil M said:   4 years ago
Your router has the address 172.16.2.1/23 on the ethernet interface which IP address can be assigned to a host connected to the ethernet interface of the router and what will be that host default gateway.
(2)

Aishwarya mishra said:   10 years ago
The valid host id is from 172.16.2.0 to 172.16.3.254 [excluding 172.16.2.1(as this is itself routers id)].

And the broadcast add is 172.16.3.255 [here we are making all the last nine bits as 1.].

Rahul Gawale said:   2 years ago
The valid host id is from 172.16.2.0 to 172.16.3.254 [excluding 172.16.2.1(as this is itself routers id)].

And the broadcast add is 172.16.3.255 [here we are making all the last nine bits as 1.].
(6)

Varun tyagi said:   9 years ago
2 is the block size.

So 0, 2, 4, 6 is N.ID.

0.1, 0.2, 0.3 to 1.254 are host.

Similarly.

2.1, 2.2, 2.3, 2.4 to 2.254, 2.255, 3.1, 3.2 to 3.254 are host.

But 3.255 are B.id and 4.0 n.id.

Adhie said:   1 decade ago
the option C is broadcast address and the others is host address.
that given address is class B (from 1st octet 172).

So here is sub network addr:

172.16.0.0
172.16.2.0
...
172.16.254.0

Jaanu said:   6 years ago
First host - 172.16.2.1
Last host - 172.16.255.254
Valid range - 172.16.2.1 - 172.16.255.254
Broad cast - 172.16.255.255.

Is this calculate in correct? Can anyone tell me?
(1)

Shahnas said:   8 years ago
What means of /23?

Can we take it as subnet mask? and why we want to calculate 32-23=9?

Guys! can you tell me the in IP address and subnet mask of this?

Akshay said:   8 years ago
How you guys calculate? The router's IP address on the E0 interface is 172.16.2.1/23, which is 255.255.254.0. How? Please tell me. I am new in subnets.

Muhammad Rahman said:   1 decade ago
If the range is like
.
.
172.16.2.253
172.16.2.254
172.16.2.255
172.16.3.0
172.16.3.1
172.16.3.2
.
.
How come 172.16.3.0 is not a valid address ?

Santhosh said:   10 years ago
The valid host id is from 172.16.2.0 to 172.16.3.254 [excluding 172.16.2.1(as this is itself routers id)].

And the broadcast add is 172.16.3.255.


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