Networking - Subnetting - Discussion

Discussion Forum : Subnetting - Subnetting (Q.No. 1)
1.
Your router has the following IP address on Ethernet0: 172.16.2.1/23. Which of the following can be valid host IDs on the LAN interface attached to the router?
  1. 172.16.1.100
  2. 172.16.1.198
  3. 172.16.2.255
  4. 172.16.3.0
1 only
2 and 3 only
3 and 4 only
None of the above
Answer: Option
Explanation:
The router's IP address on the E0 interface is 172.16.2.1/23, which is 255.255.254.0. This makes the third octet a block size of 2. The router's interface is in the 2.0 subnet, and the broadcast address is 3.255 because the next subnet is 4.0. The valid host range is 2.1 through 3.254. The router is using the first valid host address in the range.
Discussion:
35 comments Page 4 of 4.

Nikhil said:   8 years ago
How did we get the subnet mask as 255.255.254.0?

Kapil said:   7 years ago
Can any one help me to understand subnetting?

Akira said:   8 years ago
Can you please explain this from the scratch?

Sunil said:   6 years ago
Thanks for the explanation @Vikash_Jaiswal.
(1)

Sundha said:   7 years ago
How it is. Can you explain me clearly?


Post your comments here:

Your comments will be displayed after verification.