Networking - Subnetting - Discussion

The valid host range will be (172.16,2.1-172.16.3.254).

The network address : 172.16.2.0.

The broadcast address: 172,16.3.255.

The network 172.16.2.0 will ends 172.16.2.55 then it will become 172.16.3.0 which is still on the range of the network.

00000000.00000000.0000000|0.00000000.
76543210.76543210.7654321|0.76543210.
1.255.

IP starts from 2.1 and ends with 3.254. So we can't use these numbers. It means we can use 172.16.2.1 - 172.16.3.254. I think so:x.

172.16.2.0 NID.
172.16.2.1 FIRST VALID HOST.
172.16.2.255.
172.16.3.1.
172.16.3.255.
172.16.4.1.
172.16.4.254 LAST VALID HOST.
172.16.4.255 BROAD CAST.

172.16.3.0 it's not a valid address.

Between in these option valid address is 172.16.2.255

Can you please explain this from the scratch?

How did we get the subnet mask as 255.255.254.0?

@Nikhil.

Because 7 bits are opened in the third octet.

Guys What I think is.

Block size is 2(256-254:FROM LAST NON-ZERO OCTET IN SUBNET MASK).
So the subnets would be divided by a factor of 2.

Starting from
172.16.0.0-172.16.1.255(including a network address and broadcast address).

As we are considering E0 starting from _._.2.1.

The subnet it comes under is as 127.16.2.0(being n/w id) and the flow is as follows:
172.16.2.0 NID.
172.16.2.1 FIRST VALID HOST.
172.16.2.255.
172.16.3.0 *VALID ADDRESS(as it is not a n/w id).
172.16.3.1.
172.16.3.254 LAST VALID HOST.
172.16.3.255. BROAD CAST.

According to which it should be none of these networks.
Hope it will help you.

How you guys calculate? The router's IP address on the E0 interface is 172.16.2.1/23, which is 255.255.254.0. How? Please tell me. I am new in subnets.

23 is a prefix length. So IPV4 has 32 bit of address.

32 - 23 = 9. Now IP address of ethernet 0 is 172.62.2.1/23.

If we want to find out first address than we have to set 9 (32 - 23 = 9) rightmost bit as zero.

10101100.00111110.00000010.00000000 = 172.62.2.1.

So, the first address is 172.62.2.1.

last address -> put 9 rightmost bit as 1.

10101100.00111110.00000011.11111111 = 172.62.3.255.

So the range = 172.62.2.1 to 172.62.3.255.

How can be 172.168.3.0 is a host id? It is a network id.