Networking - Subnetting - Discussion
Discussion Forum : Subnetting - Subnetting (Q.No. 1)
1.
Your router has the following IP address on Ethernet0: 172.16.2.1/23. Which of the following can be valid host IDs on the LAN interface attached to the router?
- 172.16.1.100
- 172.16.1.198
- 172.16.2.255
- 172.16.3.0
Answer: Option
Explanation:
The router's IP address on the E0 interface is 172.16.2.1/23, which is 255.255.254.0. This makes the third octet a block size of 2. The router's interface is in the 2.0 subnet, and the broadcast address is 3.255 because the next subnet is 4.0. The valid host range is 2.1 through 3.254. The router is using the first valid host address in the range.
Discussion:
34 comments Page 4 of 4.
Mohamad Fazil M said:
3 years ago
Your router has the address 172.16.2.1/23 on the ethernet interface which IP address can be assigned to a host connected to the ethernet interface of the router and what will be that host default gateway.
(1)
Babu said:
3 years ago
@All.
We have to understand host range is 1 to 254,0 and 255 is network & broadcast ID REMEMBER Only first and last bits Network & Broadcast ID.
So 172.16.2.1 to 172.16.2.255 then next change 172.16.3.0 to 172.16.3.255 Because we have 2^9-2=510 hosts.
That's why 3.254 is valid one So 2.55 is not Broadcast ID.
I hope you will understand.
We have to understand host range is 1 to 254,0 and 255 is network & broadcast ID REMEMBER Only first and last bits Network & Broadcast ID.
So 172.16.2.1 to 172.16.2.255 then next change 172.16.3.0 to 172.16.3.255 Because we have 2^9-2=510 hosts.
That's why 3.254 is valid one So 2.55 is not Broadcast ID.
I hope you will understand.
(2)
Malede said:
2 years ago
It is very helpful. Thanks everyone for explaining.
(1)
Rahul Gawale said:
1 year ago
The valid host id is from 172.16.2.0 to 172.16.3.254 [excluding 172.16.2.1(as this is itself routers id)].
And the broadcast add is 172.16.3.255 [here we are making all the last nine bits as 1.].
And the broadcast add is 172.16.3.255 [here we are making all the last nine bits as 1.].
(1)
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