Networking - Subnetting - Discussion

class c
192.168.2.0

Subnets = 5.
Hosts = 16.

128 64 32 16 8 4 2 1
1 1 1 0 0 0 0 0.
and

2^5 - 2=30 host
2^3 = 8 subnets.
So,
255.255.255.224.

5 subnets 16 hosts

First, you have to meet the number of the host which is 16. By borrowing 4 bits we will meet 16 hosts but there will be no room for the network and broadcast address so we will use 5 bits that has 32 hosts. Using the 2^5 -2 will give us 30 which satisfy our required number of hosts.

Secondly, we will use the formula an actual number of network = 32 (by default) minus no. of borrowed bits so 32-5 equals 27.

Our new subnet mask is /27 which is equivalent to 255.255.255.224.

225.255.255.192=/26 so 24+2(2N we need to borrow) formula 2^2=4 subnets.
for hosts 256-192=64 hosts.
255.255.255.224=/27 so 24+3(3n we need to borrow)formula 2^n=2^3=8 sub.
for hosts 256-224=32 hosts.
255.255.255.240=/28 so 24+4(4N we need to borrow) formula 2^N=16 subnets.
for hosts 256-240=16 hosts.

Prove if a host on a network has the address 172.16.45.14/30, the broadcast address of the subnet is 172.16.45.15.

Suppose you are given the following class C IP address: 192.100.1.1. You need to perform Subnetting in such a way that you get 3 (three) subnets such that each subnet contains 62 (sixty two) valid hosts.

You need to specify the network and broadcast address of each subnet and the valid host range in each of the subnet. Please solve it as early as possible.

Good, Thanks all.

16 hosts < 32, 32 = 2^5, so it takes 5 bits, and each subnet has 30 hosts.
32 " 5 = 27, it means the subnet-mask has /27 bits.

5 subnets < 8, 8 = 2^3,
therefore, 27 " 3 = 24 bits,
= 255.255.255.0.

8 subnets x 32 IPs " 2 = 254, the answer should be 255.255.255.0.

For example class c IP, 192.168.1.1/24 with subnet-mask 255.255.255.224.

16 hosts < 32, 32 = 2^5, so it takes 5 bits, and each subnet has 30 hosts.
32 " 5 = 27, it means the subnet-mask has /27 bits.

5 subnets < 8, 8 = 2^3,
therefore, 27 " 3 = 24 bits,
= 255.255.255.0.

8 subnets x 32 IPs " 2 = 254, the answer should be 255.255.255.0.

For example class c IP, 192.168.1.1/24 with subnet-mask 255.255.255.224.

4 subnets, each with at least 20 hosts. Which subnet mask? Please explain about it.

I need formula 2^16=32 value of network.

So I taken 128.64.32. value mention after another 0.0.0.0.0 calculate 128+64+32=224.
Ans 255.255.255.224.