Networking - Subnetting - Discussion

Discussion Forum : Subnetting - Subnetting (Q.No. 12)
12.
You have an interface on a router with the IP address of 192.168.192.10/29. What is the broadcast address the hosts will use on this LAN?
192.168.192.15
192.168.192.31
192.168.192.63
192.168.192.127
Answer: Option
Explanation:
A /29 (255.255.255.248) has a block size of 8 in the fourth octet. This means the subnets are 0, 8, 16, 24, etc. 10 is in the 8 subnet. The next subnet is 16, so 15 is the broadcast address.
Discussion:
4 comments Page 1 of 1.

Mehedi hasan said:   8 years ago
I think all both of them are broadcast address for the network with subnet mask/29.

Taran said:   8 years ago
Block Size = 8.

192.168.192.0
192.168.192.8 >> 192.168.192.10 lies there. So B. Add. is 192.168.192.15
192.168.192.16
192.168.192.24

MURENZI RWABUHUNGU said:   6 years ago
Block Size = 8.

Sukhjeet said:   6 years ago
How to find subnets when host bit are given?

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