Networking - Subnetting - Discussion

Discussion Forum : Subnetting - Subnetting (Q.No. 2)
2.
Which two statements describe the IP address 10.16.3.65/23?
  1. The subnet address is 10.16.3.0 255.255.254.0.
  2. The lowest host address in the subnet is 10.16.2.1 255.255.254.0.
  3. The last valid host address in the subnet is 10.16.2.254 255.255.254.0.
  4. The broadcast address of the subnet is 10.16.3.255 255.255.254.0.
1 and 3
2 and 4
1, 2 and 4
2, 3 and 4
Answer: Option
Explanation:
The mask 255.255.254.0 (/23) used with a Class A address means that there are 15 subnet bits and 9 host bits. The block size in the third octet is 2 (256 - 254). So this makes the subnets in the interesting octet 0, 2, 4, 6, etc., all the way to 254. The host 10.16.3.65 is in the 2.0 subnet. The next subnet is 4.0, so the broadcast address for the 2.0 subnet is 3.255. The valid host addresses are 2.1 through 3.254.
Discussion:
37 comments Page 2 of 4.

Shailendra kumar yadav said:   8 years ago
The lowest host address in the subnet is 10.16.2.1 255.255.254.0.

It is incorrect because the lowest host address in the subnet is 10.16.3.254 255.255.254.0.

Ikechukwu said:   1 decade ago
I do not understand how option B is the correct answer. I would have thought that option 1 is the only correct description for the IP address.

Rohit said:   10 years ago
How come 10.16.2.254 255.255.254.0 is not a valid address keeping in mind that valid address for hosts range from 10.16.2.1 to 10.16.3.254?

Rocky said:   3 years ago
I didn't get the proper explanation.

So, please explain to me properly. (10.16.0.1 - 10.16.0.254) is this the correct range?
(2)

Ali said:   9 years ago
After calculating how did we come to know that "the possible networks will be 10.16.2.1 to 10.16.3.254"?

Vaishali said:   1 decade ago
I thought it is a class B address. How can it be class A address? and how the subnet bits can be 15 in this?

Venkatesh said:   7 years ago
The subnet mask for the mentioned IP address is 255.255.254.0 then option 1 is also correct right.
(3)

Arunkumar said:   9 years ago
Option C is correct.

The subnet is 255.255.254.0 for10.16.3.0 because the CIDER value is 23.
(1)

Santhosh said:   1 decade ago
The valid host id is from 10.16.2.1 to 10.16.3.254.

And the broadcast add is 10.16.3.255.

Aryan said:   9 years ago
255.255.254.0 is the subnet mask for the network right?

Then why not option C is correct?
(1)


Post your comments here:

Your comments will be displayed after verification.