Networking - Networking Basics - Discussion
Discussion Forum : Networking Basics - Networking Basics (Q.No. 7)
7.
Which of the following is the valid host range for the subnet on which the IP address 192.168.168.188 255.255.255.192 resides?
Answer: Option
Explanation:
256 - 192 = 64. 64 + 64 = 128. 128 + 64 = 192. The subnet is 128, the broadcast address
is 191, and the valid host range is the numbers in between, or 129-190.
Discussion:
46 comments Page 5 of 5.
SANJAY SINGHANIYA said:
9 years ago
Please explain other very simple method.
Rashidalamsiwani said:
7 years ago
Subnet should be C 192.168.168.128-190.
Harish said:
9 years ago
64 - 2 = 62 then b is the answer.
Daniel Ajo said:
7 years ago
Where did 156-192 come from?
Varun said:
8 years ago
Thank you @Lavanya S S.
Sivakrishna said:
7 years ago
Thank you @Jitendra.
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