Networking - Networking Basics - Discussion
Discussion Forum : Networking Basics - Networking Basics (Q.No. 7)
7.
Which of the following is the valid host range for the subnet on which the IP address 192.168.168.188 255.255.255.192 resides?
Answer: Option
Explanation:
256 - 192 = 64. 64 + 64 = 128. 128 + 64 = 192. The subnet is 128, the broadcast address
is 191, and the valid host range is the numbers in between, or 129-190.
Discussion:
46 comments Page 4 of 5.
Anan said:
2 years ago
How do know the subnet mask is /26? Please explain the concept in clear.
(2)
Srinu said:
8 years ago
Why other options are in correct, anyone can explain it briefly?
Punith said:
9 years ago
@Shyamnarayan.
Your answer is perfect with the simple solution.
Your answer is perfect with the simple solution.
Shahnawaz said:
1 decade ago
I didn't understand. Can anyone explain me clearly please?
Guru said:
1 decade ago
I didn't understand, please. Can anyone explain clearly.
Hitanshi said:
8 years ago
Hi, I am not getting this, Please explain it in detail.
Vivek singh rathore said:
9 years ago
Not getting the solution, please explain me in detail.
Sumit said:
8 years ago
The correct answer will be 192.168.168.128 - 191.
Madhu said:
8 years ago
How you get 192.168.168.191 as broadcast id?
Shami said:
8 years ago
I can't understand. Please anyone help me.
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