Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 1 (Q.No. 38)
38.
One kg of carbon monoxide requires __________ kg of oxygen to produce 11/7 kg of carbon dioxide gas.
Discussion:
22 comments Page 1 of 3.
Aritra Ghosh said:
1 decade ago
2CO + O2 = 2 CO2
(2*28) (16*2) (2*44)
=56 kg =32 kg =88 kg
=1 kg =32/56 kg =88/56 kg
=1 kg =4/7 kg =11/7 kg
That is 4/7 kg of O2 is required for preaparing 11/7 kg of CO2 from 1 kg CO.
(2*28) (16*2) (2*44)
=56 kg =32 kg =88 kg
=1 kg =32/56 kg =88/56 kg
=1 kg =4/7 kg =11/7 kg
That is 4/7 kg of O2 is required for preaparing 11/7 kg of CO2 from 1 kg CO.
(15)
Imran said:
8 years ago
1 + 4/7 = 11/ 7.
(4)
Mayur said:
9 years ago
We can also do it easily by mass conservation:
The reaction is : 2CO+O2=2CO2,
So basically Total mass of CO2 will be equal to sum of masses of CO and O2. Hence.
1+O2=11/7.
Mass of O2=11/7-1=4/7.
(The stoichiometric coefficients won't matter as we are directly doing mass conservation).
The reaction is : 2CO+O2=2CO2,
So basically Total mass of CO2 will be equal to sum of masses of CO and O2. Hence.
1+O2=11/7.
Mass of O2=11/7-1=4/7.
(The stoichiometric coefficients won't matter as we are directly doing mass conservation).
(2)
Atanu pal said:
5 years ago
Thanks for Explaining.
(1)
Rahul s said:
8 years ago
Thank you all for the given explanations.
Naveen said:
6 years ago
Thanks for explaining.
Kamlesh said:
8 years ago
Give explanation.
Sk Ajijur said:
8 years ago
Thanks for the explanation.
ATC said:
8 years ago
Nice explanation @Aritra.
A B Manju said:
8 years ago
Nice, explanation thank you.
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