Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 5 (Q.No. 30)
30.
Which of the following is the correct statement?
Discussion:
36 comments Page 1 of 4.
RAM MOHAN said:
8 years ago
Both A & D is correct.
Explanation:
A: All the reversible engines have the same efficiency.
Efficiency of Carnot=Erricson=Stirling is same.
D: Actually, Engines are designed as per reversible cycle (Theoretically), But practically that won't occur s due to (Friction, Unstrained expansion, Heat Transfer through finite difference etc).
Explanation:
A: All the reversible engines have the same efficiency.
Efficiency of Carnot=Erricson=Stirling is same.
D: Actually, Engines are designed as per reversible cycle (Theoretically), But practically that won't occur s due to (Friction, Unstrained expansion, Heat Transfer through finite difference etc).
Ankit Korde said:
8 years ago
I think there is difference between engine and cycle.
As Otto cycle has maximum efficiency than Diesel cycle but efficiency of petrol engine is less than Diesel engine.
So reversible cycle has maximum efficiency but reversible engine has less efficiency than irreversible engine. So answer is C.
As Otto cycle has maximum efficiency than Diesel cycle but efficiency of petrol engine is less than Diesel engine.
So reversible cycle has maximum efficiency but reversible engine has less efficiency than irreversible engine. So answer is C.
Vijay patel said:
10 years ago
Yes. Option A is write answer. Because all reversible engine are working on carnot cycle, in which the losses are not considered. And that provide the system reversibility. When losses are not considered then for given heat input the engine will give maximum work.
Anupam pandey said:
1 decade ago
Option A is correct. As per carnot principle : (1) all the reversible engine working between same temperatures have same Efficiency.
(2) reversible engine have always higher efficiency than irreversible engine working between same temperature range.
(2) reversible engine have always higher efficiency than irreversible engine working between same temperature range.
Mukesh said:
6 years ago
D is correct option and A is incorrect because Otto cycle, diesel cycle, all are reversible but they have less efficiency then carnot cycle and also stirling and Ericsson cycle have equal efficiency to that of carnot cycle when regenerative is used.
Sharko said:
9 years ago
I think option D is correct because if you see all the heat engine diagram, they are all cyclic hence reversible. And the reason why they are made to operate in cyclic or reversible range is because you get highest efficiency in that range.
Hussain said:
9 years ago
Option A is also incorrect as reversible engines operating between different temperature limit will have different efficiency.
Operating between same temperature limit is not stated.
Operating between same temperature limit is not stated.
Haiyalappa Bangalore said:
9 years ago
Option A is the right answer because Carnot engine is an ideal and no losses are considered.
Hence, which has more efficiency than irreversible engines.
Hence, which has more efficiency than irreversible engines.
Raushan said:
9 years ago
Option D is correct. We know that Carnot engine has a maximum efficiency that is valid for reversible engine only. So, option D is correct.
Kishor said:
9 years ago
In irreversible engine heat losses takes place. So the efficiency of Carnot is alway higher than irreversible. So option A is correct.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers