Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 4 (Q.No. 47)
47.
One reversible heat engine operates between 1600 K and T2 K and another reversible heat engine operates between T2 K and 400 K. If both the engines have the same heat input and output, then temperature T2 is equal to
Discussion:
14 comments Page 2 of 2.
Mori bhavdip said:
7 years ago
Both are the reversible engines and efficiency of all reversible engines are same so we can compare the efficiency equation and get the answer.
T1-T2/Ti = T2-T3/T2.
T1-T2/Ti = T2-T3/T2.
(1)
SAIROHIT SANDELA said:
7 years ago
Same heat input and output.
Means efficiencies are the same.
For the same efficiencies, the intermediate temperature is the geometric mean of the other two extreme temperatures.
If work done in both cases is the same then that would be the average of the two temperatures.
Means efficiencies are the same.
For the same efficiencies, the intermediate temperature is the geometric mean of the other two extreme temperatures.
If work done in both cases is the same then that would be the average of the two temperatures.
(1)
Girish baswa said:
7 years ago
In question it is not mentioned that both heats engines are in series, so for same heat input and workput the efficiency will remain same and the answer is geometric mean of it.
(1)
GATE 2018 guy said:
5 years ago
If heat input and output are same, then the work done must also be the same right?
Then T2 = (1600+400) /2.
T2 = 1000 K can also be the right answer.
Then T2 = (1600+400) /2.
T2 = 1000 K can also be the right answer.
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers