Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 4 (Q.No. 47)
47.
One reversible heat engine operates between 1600 K and T2 K and another reversible heat engine operates between T2 K and 400 K. If both the engines have the same heat input and output, then temperature T2 is equal to
Discussion:
14 comments Page 1 of 2.
GATE 2018 guy said:
5 years ago
If heat input and output are same, then the work done must also be the same right?
Then T2 = (1600+400) /2.
T2 = 1000 K can also be the right answer.
Then T2 = (1600+400) /2.
T2 = 1000 K can also be the right answer.
(1)
Girish baswa said:
7 years ago
In question it is not mentioned that both heats engines are in series, so for same heat input and workput the efficiency will remain same and the answer is geometric mean of it.
(1)
SAIROHIT SANDELA said:
7 years ago
Same heat input and output.
Means efficiencies are the same.
For the same efficiencies, the intermediate temperature is the geometric mean of the other two extreme temperatures.
If work done in both cases is the same then that would be the average of the two temperatures.
Means efficiencies are the same.
For the same efficiencies, the intermediate temperature is the geometric mean of the other two extreme temperatures.
If work done in both cases is the same then that would be the average of the two temperatures.
(1)
Mori bhavdip said:
7 years ago
Both are the reversible engines and efficiency of all reversible engines are same so we can compare the efficiency equation and get the answer.
T1-T2/Ti = T2-T3/T2.
T1-T2/Ti = T2-T3/T2.
(1)
Mani said:
7 years ago
Thank you all for the explanation.
M S NAYAK said:
8 years ago
If the efficiency of two engines are same,
Intermediate temperature T2 = root(T1*T3).
If work output is same.
T2 = (T1+T2)/2.
Intermediate temperature T2 = root(T1*T3).
If work output is same.
T2 = (T1+T2)/2.
(1)
Bibin Emmanuvel said:
8 years ago
I think Both A and B are correct.
Murali said:
8 years ago
Thank you so much for the given explanation.
Pavan said:
8 years ago
Work done is also same in both the cases, so option B might be correct.
Shiva said:
10 years ago
The geometric mean is for heat engine in series. In this case the heat rejected by the first engine is given as input to second engine.
The question says same heat supplied as input.
The question says same heat supplied as input.
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