Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 3 (Q.No. 36)
36.
The ratio of molar specific heats for monoatomic gas is
Discussion:
12 comments Page 1 of 2.
Satya said:
1 decade ago
Ratio of Specifics heat of gases is calculated by using the following formula 1+2/x.
Where x = 1 for mono atomic gas.
x = 2 for Diatomic gas.
x = 3 for Tri atomic gas etc.
Where x = 1 for mono atomic gas.
x = 2 for Diatomic gas.
x = 3 for Tri atomic gas etc.
Mmj said:
1 decade ago
But here mono atomic gas then 1+2/1=3.
Vaishali said:
1 decade ago
Tell me anyone the correct formula for finding the ratio of molar specific heat of gases.
NAVIN said:
1 decade ago
Molar specific heat at constant pressure = 5/2*R.
Molar specific heat at constant volume is = 3/2*R
So Pm/Vm = 5/2*2/3 = 5/3 = 1.67
Molar specific heat at constant volume is = 3/2*R
So Pm/Vm = 5/2*2/3 = 5/3 = 1.67
Rayudu said:
1 decade ago
1+2/x.
Where,
x = 3 for monotonic.
x = 5 for diatomic.
x = 6 for triatomic.
And x is degrees of freedom.
Where,
x = 3 for monotonic.
x = 5 for diatomic.
x = 6 for triatomic.
And x is degrees of freedom.
RISHI said:
9 years ago
1 + 2/f where f is the deg of freedom and for monoatomic gas DOF IS 3 hence 1 + 2/f = 1.67. So it is the answer.
S Bera said:
8 years ago
X=4 dof for monoatomic, x=5 dof for diastolic, x=6 dof for triatomic.
Krupa said:
7 years ago
How to find DoF?
Krupa said:
7 years ago
How to find DOF for gas?
Srinu@v said:
7 years ago
The kinetic energy of one molecule in a particular direction.
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