Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 3 (Q.No. 41)
41.
The area under the temperature-entropy curve (i. e. T - s curve) of any thermodynamic process represents the workdone during the process.
Discussion:
17 comments Page 1 of 2.
Berhe said:
3 years ago
T-S curve gives total amount of heat rejection or absorption.
(1)
Rahul said:
8 years ago
Right, I agree with you @Mayur.
(1)
Sagar said:
9 years ago
Net work done= Net heat transfer = tds output - tds input.
Rajnish shukla said:
5 years ago
As we know that are under pressure value gives WD and similar area under TS diagram gives net Heat transfer but according to first law of TD both are same things for a cycle so answer should be correct.
Sudheer said:
6 years ago
Please explain the correct answer.
Brajesh said:
7 years ago
The area under T-S curve represent heat added or removed? Please tell me.
Sushil said:
7 years ago
@Rahul question is asking for processes.
I think in the case of cycle both the curve represent work done.
I think in the case of cycle both the curve represent work done.
Abhay padhiyar said:
8 years ago
Here, p-v=net work done.
t-s=total amount of heat.
t-s=total amount of heat.
Manish kotia said:
8 years ago
Which process in which area under curve is constant?
Mandar said:
1 decade ago
The area under curve p-v represents work done and area under curve t-s represent entropy.
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