Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 3 (Q.No. 50)
50.
The heat absorbed or rejected by the working substance is given by (where ds = Increase or decrease of entropy, T = Absolute temperature, and dQ = Heat absorbed or rejected)
Discussion:
3 comments Page 1 of 1.
Suresh yadav said:
7 years ago
Entrpoy is ds=dQ/t.
Arvind Yadav said:
7 years ago
We know that ds=(δ) Q/T,
So (δ)Q = T.ds.
So (δ)Q = T.ds.
Naveen said:
8 years ago
Please give the correct description.
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