Mechanical Engineering - Thermodynamics - Discussion

Discussion Forum : Thermodynamics - Section 5 (Q.No. 28)
28.
The entropy may be expressed as a function of
pressure and temperature
temperature and volume
heat and work
all of these
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
23 comments Page 1 of 3.

Future learn said:   5 years ago
Entropy as a function of temperature and volume.

We can express the entropy as a function of temperature and volume.

It can be derived from the combination of the first and the second law for the closed system.

For an ideal gas, the temperature dependence of entropy at constant volume is simply Cv over T.

The volume dependence of entropy at constant temperature is are over volume for ideal gases.

Vipul said:   7 years ago
Entropy is a point function which is a property of the system, thus it can be expressed in the form of other point functions, which is also obvious from tds relations. Next, like internal energy which is a point function but can be expressed as function of heat and work (Ist law) so does entropy so correct option is D.

Hussain said:   9 years ago
I Bilieve that a and b answer is correct.

Because from two property rule, any property can be expressed as the function of any other two property.

Heat and work are path function and not property of the system.
(1)

ASURA said:   7 years ago
Entropy being an extensive property depends only on temperature and pressure which are also extensive properties if it is function of volume it would not be a extensive property as volume itself is not extensive.

Vivek said:   10 years ago
Entropy is a function pressure and temperature, volume and temperature, pressure and volume. Also, Entropy = Heat supplied/temperature. So, the correct answer is option (D) all of these.

Om Nagar said:   8 years ago
Work is high grade energy so entropy can not be expresse as function of work,

Entropy express as function of T&P, T&V, and heat.

So correct answer is A&B.

Sweta said:   8 years ago
Tds = U+pdV.
Q = T * dS.

UnAvailable energy = f(W) = f(S) where f means function.

It can be expressed in both volume and pressure as well as temperature.

Hardik gohil said:   9 years ago
According to me, answer A and B both are correct. Answer C is not because entropy change is associate with flow of heat only not with flow of work.

JAIMIN said:   10 years ago
I agree with you @Vivek.

Because the three equations of TDS came out from expressing entropy as fun of p & v, p & t and t & v.

Siva said:   8 years ago
Entropy is a function of temperature it is independent of pressure and volume.

Then how? pressure is given.


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