Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 1 (Q.No. 6)
6.
An adiabatic process is one in which
Discussion:
49 comments Page 2 of 5.
Mithilesh kumar said:
1 decade ago
According to the rule of adiabatic no heat interaction will occur. Then how change in gas temp will be adiabatic?
Prashanthi said:
1 decade ago
Adiabatic changes in temperature occur due to changes in pressure of a gas while not adding or subtracting any heat. In contrast, free expansion is an isothermal process for an ideal gas.
Pawan said:
1 decade ago
In adiabatic process q=0.
Then all the above conditions satisfied.
Then all the above conditions satisfied.
Parveen said:
1 decade ago
In this process no heat is added or withdrawn from the system so how another process can happen only a option is true another one is wrong.
Vasanth kumar said:
1 decade ago
As per adiabatic process assumption there will be no heat transfer in or out of the system. First condition is satisfied.
The internal energy within cause the work, So that temperature changes.
As per first law of thermodynamics dQ equals to du+dw.
Heat transfer is zero du equal -dw. So that third is also correct.
The internal energy within cause the work, So that temperature changes.
As per first law of thermodynamics dQ equals to du+dw.
Heat transfer is zero du equal -dw. So that third is also correct.
Muthamizh Selvan said:
1 decade ago
What is the relationship between internal energy and temperatures?
Saravanakumar said:
1 decade ago
@Muthamizh Selvan There is one.
Q = Del E + Del W.
Del E = dU+ dE, here dU is the heat produced due to work. So there is heat energy is induced inside the system, there the temperature will changes. Still there is no heat transfer across the boundary, Since the process is adiabatic.
Del W = Del W.
Q = Del E + Del W.
Del E = dU+ dE, here dU is the heat produced due to work. So there is heat energy is induced inside the system, there the temperature will changes. Still there is no heat transfer across the boundary, Since the process is adiabatic.
Del W = Del W.
Aarti Mirge said:
1 decade ago
As per second law of thermodynamics, dQ=TdS, in adiabatic process dS=0, so dQ=0.
And hence dU=-dW, i.e, work is done on account of internal energy and as internal energy is a function of temperature for an ideal gas so temp will change although there is no heat transfer in adiabatic process.
And hence dU=-dW, i.e, work is done on account of internal energy and as internal energy is a function of temperature for an ideal gas so temp will change although there is no heat transfer in adiabatic process.
Divakar mishra said:
1 decade ago
Because in the adiabatic process dq=0 then t=c.
Irfan Ansari said:
1 decade ago
As it is an adiabatic process so, no heat enters or leaves the system.
Dq = du+dw.
O = du = 0.
Dq = du+dw.
O = du = 0.
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