Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 2 (Q.No. 40)
40.
The gas constant (R) is equal to the __________ of two specific heats.
Discussion:
5 comments Page 1 of 1.
Kalyan said:
2 years ago
@All.
The difference means (-).
i.e cp-cv=R.
The difference means (-).
i.e cp-cv=R.
K. Vamshi said:
5 years ago
Cp-Cv = R.
Prashant said:
8 years ago
This is Called Meyer's equation.
Venkat said:
9 years ago
Cp is specific heat at constant pressure.
Cv is specific heat at constant volume.
From the enthalpy definition,
h = u + pv.
Differentiate it and pv = RT(for one mole of ideal gas).
dh = du + d(RT).
cpdt = Cvdt + Rdt.
Cancel the dt, Then we get,
Cp = Cv + R.
Cv is specific heat at constant volume.
From the enthalpy definition,
h = u + pv.
Differentiate it and pv = RT(for one mole of ideal gas).
dh = du + d(RT).
cpdt = Cvdt + Rdt.
Cancel the dt, Then we get,
Cp = Cv + R.
Saurabh said:
1 decade ago
R = Cp-Cv.
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