Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 1 (Q.No. 36)
36.
According to Avogadro's law, the density of any two gases is __________ their molecular masses, if the gases are at the same temperature and pressure.
Discussion:
8 comments Page 1 of 1.
Rahul said:
7 years ago
At a same tem and pressure contain equal no volume.
Vishnu said:
8 years ago
Avogadro's law.
A law stating that equal volumes of gases at the same temperature and pressure contain equal numbers of molecules.
A law stating that equal volumes of gases at the same temperature and pressure contain equal numbers of molecules.
VRC said:
9 years ago
VRC,
As per Avogadro's law v1/v2=n1/n2,
Also we know that density (d)=m/v.
That's why density is directly proportional to molecular masses.
As per Avogadro's law v1/v2=n1/n2,
Also we know that density (d)=m/v.
That's why density is directly proportional to molecular masses.
Ravinder Naik said:
10 years ago
What is Avogadro's law, and explain with any formula?
Sudarshan said:
1 decade ago
That two given samples of an ideal gas, of the same volume and at the same temperature and pressure, contain the same number of molecules.
Hence the density of any two gases is directly proportional to their molecular masses.
Hence the density of any two gases is directly proportional to their molecular masses.
(1)
Saikumar said:
1 decade ago
V is directly proportional to n at same temperature and pressure.
V is the volume of the gas.
n is the amount of substance of the gas (measured in moles).
Density = mass/volume.
So by according to avogadro's law density is directly proportional to mass at same temp and pressure.
V is the volume of the gas.
n is the amount of substance of the gas (measured in moles).
Density = mass/volume.
So by according to avogadro's law density is directly proportional to mass at same temp and pressure.
Ahasan_ashish said:
1 decade ago
d=(PM)/(RT) so d is proportional to M.
SAGAR said:
1 decade ago
p = 9Rt, at same temperature and pressure, 9 depends on R, R is a characteristic gas constant, R=Ru\M(M=molecular weight of air) but here we need to consider the molecular weight of gases.
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