Mechanical Engineering - Theory of machines - Discussion
Discussion Forum : Theory of machines - Section 9 (Q.No. 22)
22.
A torsional system with discs of moment of inertia I1 and I2 as shown in the below figure, is gear driven such that the ratio of speed of shaft B to shaft A is 'G'. Neglecting the inertia of gears, the equivalent inertia of disc on shaft B at the speed of shaft A is equal to
Discussion:
3 comments Page 1 of 1.
Meet said:
8 years ago
Equivalent inertia of disc B = m.i. of disc B/ (gear ratio)2.
gear ratio=n1/n2
m.i. of B=I2
So, equi. inertia of B=I2/(n1/n2) = I2*G^2 (besause G=n2/n1).
gear ratio=n1/n2
m.i. of B=I2
So, equi. inertia of B=I2/(n1/n2) = I2*G^2 (besause G=n2/n1).
Pratap said:
9 years ago
Please explain this answer?
Raffa said:
9 years ago
Can someone explain this answer?
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