Mechanical Engineering - Theory of machines - Discussion
Discussion Forum : Theory of machines - Section 1 (Q.No. 3)
3.
In a vibrating system, if the actual damping coefficient is 40 N/m/s and critical damping coefficient is 420 N/m/s, then logarithmic decrement is equal to
Discussion:
27 comments Page 2 of 3.
Mithun Kumar said:
7 years ago
Since ln(x0/x1)= 2 * π*zeta/√ (1-zeta^2).
Where zeta=actual damping coefficient/critical damping coefficient.
Where zeta=actual damping coefficient/critical damping coefficient.
PRINCE KUMAR said:
8 years ago
@Pranay Mishra.
Logarithmic decrement is the rate through which amplitude of free damped vibration is decreases.
It is only for under damped vibration system.
Logarithmic decrement is the rate through which amplitude of free damped vibration is decreases.
It is only for under damped vibration system.
Nagamalleswarao said:
9 years ago
Could you please confirm the zeta. Is this zeta is a damping factor or damping coefficient, or both are same?
Mohan said:
9 years ago
Good explanation. Thank you all.
Kareena shah said:
9 years ago
Perfect answer @Jithin.
BHEEMESH said:
1 decade ago
Logarithmic Decrement = 2*(Pi)*Zeta/sqrt(1-zeta^2).
Where zeta = Actual damping coefficient/Critical damping coefficient.
Where zeta = Actual damping coefficient/Critical damping coefficient.
Vicky pooraneeswar said:
9 years ago
Can anyone please explain in a simple way?
Ramu said:
9 years ago
Zeta is damping factor or damping ratio.
Rohit said:
9 years ago
May be Zeta is the damping coefficient.
Peviks said:
9 years ago
Thank you all, it great to understand the solution.
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