Mechanical Engineering - Theory of machines - Discussion
Discussion Forum : Theory of machines - Section 1 (Q.No. 39)
39.
A shaft has an attached disc at the centre of its length. The disc has its centre of gravity located at a distance of 2 mm from the axis of the shaft. When the shaft is allowed to vibrate in its natural bow-shaped mode, it has a frequency of vibration of 10 rad/s. When the shaft is rotated at 300 r.p.m., it will whirl with a radius of
Discussion:
6 comments Page 1 of 1.
Shah said:
1 decade ago
y = e/((1-(wn/w)^2)).
Given,
e = 2mm.
wn = 10rad/s.
w = 300rpm = 31.4 rad/s.
Hence,
y = 2.22mm.
Given,
e = 2mm.
wn = 10rad/s.
w = 300rpm = 31.4 rad/s.
Hence,
y = 2.22mm.
(1)
Bks said:
1 decade ago
r = ((w/wn)^2*e)/1-(w/wn)^2.
Pravin said:
9 years ago
How to convert rpm into rad/sec?
Bindumadhavi said:
9 years ago
@Pravin.
(300 * 2pi)/60 = 31.4rad/sec.
(300 * 2pi)/60 = 31.4rad/sec.
Vinith said:
6 years ago
1rad per sec =1rps.
1rps= 60rpm.
1rps= 60rpm.
Sai Bharath said:
5 years ago
y=e/(((wn/w)^2)-1).
Given,
e=2mm,
Wn=10rad/sec.
W = 300rpm = 300 * ((2*pi)/60) rad/sec =10pi = 31.4rad/sec.
Substituting the values of e, Wn and W in y formula we get;
y=-2.247mm.
Since the length cannot be in negative we select the option choice 2. ie 2.22mm.
Given,
e=2mm,
Wn=10rad/sec.
W = 300rpm = 300 * ((2*pi)/60) rad/sec =10pi = 31.4rad/sec.
Substituting the values of e, Wn and W in y formula we get;
y=-2.247mm.
Since the length cannot be in negative we select the option choice 2. ie 2.22mm.
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