Mechanical Engineering - Theory of machines - Discussion

Discussion Forum : Theory of machines - Section 2 (Q.No. 24)
24.
Maximum fluctuation of energy in a flywheel is equal to (where I = Mass moment of inertia of the flywheel, E = Maximum fluctuation of energy, CS = Coefficient of fluctuation of speed, and ω = Mean angular speed = )
Iω(ω1 - ω2)
Iω2CS
2ECS
all of these
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
8 comments Page 1 of 1.

SAI said:   4 years ago
I think option B should be correct as it is only the general formula and all other are some cases of maximum energy.

Shivam said:   4 years ago
The coefficient of fluctuation C's = (W1 - W2)/W.
Maximum fluctuation of energy, E = (IW^2)/2.
Substituting these values in option B & C, you'll get option A.

Hence, all are correct.

Saurav dwivedi said:   7 years ago
I think option B is correct.

Akash said:   7 years ago
Please explain option C.

Srk said:   7 years ago
The coefficient of fluctuation C's = (W1 - W2)/W.

Substitute this Cs value in option B. then you will get option A.

Yogesh said:   8 years ago
Give the correct explanation.

Deepak said:   8 years ago
I think B should be the answer.

Tahir said:   9 years ago
How? Explain it.

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