Mechanical Engineering - Theory of machines - Discussion
Discussion Forum : Theory of machines - Section 2 (Q.No. 24)
24.
Maximum fluctuation of energy in a flywheel is equal to (where I = Mass moment of inertia of the flywheel, E = Maximum fluctuation of energy, CS = Coefficient of fluctuation of speed, and ω = Mean angular speed =
)

Discussion:
8 comments Page 1 of 1.
SAI said:
4 years ago
I think option B should be correct as it is only the general formula and all other are some cases of maximum energy.
Shivam said:
4 years ago
The coefficient of fluctuation C's = (W1 - W2)/W.
Maximum fluctuation of energy, E = (IW^2)/2.
Substituting these values in option B & C, you'll get option A.
Hence, all are correct.
Maximum fluctuation of energy, E = (IW^2)/2.
Substituting these values in option B & C, you'll get option A.
Hence, all are correct.
Saurav dwivedi said:
7 years ago
I think option B is correct.
Akash said:
7 years ago
Please explain option C.
Srk said:
7 years ago
The coefficient of fluctuation C's = (W1 - W2)/W.
Substitute this Cs value in option B. then you will get option A.
Substitute this Cs value in option B. then you will get option A.
Yogesh said:
8 years ago
Give the correct explanation.
Deepak said:
8 years ago
I think B should be the answer.
Tahir said:
9 years ago
How? Explain it.
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