Mechanical Engineering - Theory of machines - Discussion

Discussion Forum : Theory of machines - Section 9 (Q.No. 1)
1.
The dedendum circle diameter is equal to (where φ = Pressure angle)
pitch circle dia. x cos φ
addendum circle dia. x cos φ
clearance circle dia. x cos φ
pitch circle dia. x sin φ
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
2 comments Page 1 of 1.

Ganeshr said:   3 years ago
Dedendum circle diameter is nothing but a base circle diameter.

Dixit said:   5 years ago
Base circle dia- = pitch circle dia * cos π.

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