Mechanical Engineering - Theory of machines - Discussion

Discussion Forum : Theory of machines - Section 10 (Q.No. 17)
17.
The centre of percussion is below the centre of gravity of the body and is at a distance equal to
h/kG
h2/kG
kG2/h
h x kG
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
1 comments Page 1 of 1.

R.aruunkumar said:   7 years ago
The answer is Kg^2/h.
Where h is the height of the body.
Kg is the centre of gravity.

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